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Marat540 [252]
3 years ago
5

Given vectors U = (7,4) and v = (1,-1), find the sum u + v and write the

Mathematics
2 answers:
levacccp [35]3 years ago
7 0

Answer:

u + v = < 8, 3 >

Step-by-step explanation:

u + v

= < 7, 4 > + < 1, - 1 > ← add corresponding components

= < 7 + 1, 4 - 1 >

= < 8, 3 >

Varvara68 [4.7K]3 years ago
3 0
⟨u + v⟩ = ⟨x₁ + x₂ , y₁ + y₂⟩
⟨u + v⟩ = ⟨7 + 1 , 4 + (-1)⟩
⟨u + v⟩ = ⟨8 , 3⟩
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A movie theater has a seating capacity of 291. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults.
Vilka [71]
45 children 85 students and 100 adults p
5 0
3 years ago
A survey was done that asked students to indicate whether or not they have ever prepared a meal for their family.
KiRa [710]

Answer:

OK I am 85% sure on this for the 13 year old its ( 23 to 112 )

and for the older kids ( 147 to 48 ) or (23:112) (147:48)

hope it helps if it doesn't sorry.

Step-by-step explanation:

4 0
3 years ago
A professional basketball team made 37.9% of its three-point field goals in one season. If 80 three-point field goal attempts ar
kompoz [17]

Answer:

The probability that more than 35 were made is 0.14686.

Step-by-step explanation:

We are given that a professional basketball team made 37.9% of its three-point field goals in one season.

80 three-point field goal attempts are randomly selected from the season.

Let \hat p = <em>sample proportion of three-point field goals made in one season.</em>

The z-score probability distribution for the sample proportion is given by;

                           Z  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} }  ~ N(0,1)

where, p = population proprotion of three-point field goals = 37.9% = 0.379

            n = sample of three-point field goal attempts = 80

            \hat p = sample proportion of three-point field goals = \frac{35}{80} = 0.4375

Now, if 80 three-point field goal attempts are randomly selected from the season, the probability that more than 35 were made is given by = P(\hat p > 0.4375)

P(\hat p > 0.4375) = P( \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} } > \frac{0.4375-0.379}{\sqrt{\frac{0.4375(1-0.4375)}{80}} } ) = P(Z > 1.05) = 1 - P(Z \leq 1.05)

                                                                       = 1 - 0.85314 = <u>0.14686</u>

The above probability is calculated by looking at the value of x = 1.05 in the z table which has an area of 0.85314.

4 0
4 years ago
A student say that the x-intercept of the graph x + 2y=5 is the point (0,5). Why is the student incorrect?
harina [27]

Answer:

the x-intercept is found when 0 is put into the equation for y.  

Because the x-intercept is found when the function passes through the x-axis.

x+2y=5

x=5

So x=5, y=0, the point would be (5,0).

8 0
2 years ago
Read 2 more answers
7/10 + 7/100 = 77/100
tensa zangetsu [6.8K]

Answer:

what I'm am supposed to be answering

5 0
2 years ago
Read 2 more answers
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