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nalin [4]
3 years ago
15

WILL GIVE BRAINLIEST!!!

Mathematics
2 answers:
ELEN [110]3 years ago
4 0

Answer:

C is the answer.  

Step-by-step explanation:

erica [24]3 years ago
4 0

A) 4*4=16

B) 8*2=16

C) 2^3 = 2*2*2= 8

D) 2^4= 2*2*2*2 =16

Answers are A) , B) and D)

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12−(−2) over a line 12−6÷2
joja [24]

Given 12−(−2) over a line 12−6÷2

We can use PEMDAS rule and solve the expression in the order as given below:-

1. Parentheses

2. Exponents

3. Multiplication

4. Division

5. Addition

6. Subtraction

Now solving for given expression:-

\frac{12-(-2)}{12-(\frac{6}{2})}\\\\=\frac{12+2}{12-3}\\\\=\frac{14}{9}

So final answer is 14/9 i.e. 14 over 9.

7 0
3 years ago
Emmett gathered some data to compare the monthly cost of renting a one-bedroom apartment in Dallas and Austin. The data collecte
Goryan [66]

Answer:

The correct options are;

a) The city's data has the higher median monthly apartment cost of the two cities by $155

b) The city's data had the greater variability among monthly apartment costs because the standard deviation was $49.13 more than that of the other set of data

Step-by-step explanation:

The given data for the cost of renting a one-bedroom apartment in Dallas is presented as follows;

$994, $1,322, $1,075, $1,189, $1,172, $1,465, $1,215, $930, $1,090, $1,288

Which can be arranged in increasing order and analyzed to find the interquartile range, mean and standard deviation using Microsoft Excel as follows;

$930, $994, $1,075, $1,090, $1,172, $1,189, $1,215, $1,288, $1,322, and $ 1,465

The first quartile, Q₁ = $1,054.75

The third quartile, Q₃ = $1,296.5

The interquartile range = Q₃ - Q₁ = $241.75

The median = $1,180.5

The average monthly cost = $1,174

The standard deviation of the sample = $159.9597

The given data for the cost of renting a one-bedroom apartment in Austin is presented in increasing order using Microsoft Excel as follows;

$900, $950, $1,100, $1,250, $1,296, $1,375, $1,389, $1,400, $1,450, $1,495

The interquartile range, mean and standard deviation are found using Microsoft Excel as follows;

The first quartile, Q₁ = $1,062.5

The third quartile, Q₃ = $1,412.5

The interquartile range = Q₃ - Q₁ = $1,412.5 - $1,062.5 = $350

The median = $1,335.5

The average monthly cost = $1,260.5

The standard deviation of the sample = $209.0945

The difference in the median cost of the two cities is $1,335.5 - $1,180.5 = $155

Therefore, the Austin's city data has the higher median monthly apartment cost of the two cities by $155

b) The difference in the sample standard deviation of the two cities is $209.0945 - $159.9597 = $49.13476

Therefore, the Austin city data had the greater variability among monthly apartment costs because the standard deviation was $49.13 more than that of the other set of data.

7 0
3 years ago
Read 2 more answers
Using graph paper, determine the line described by the given point and slope. Click to show the correct graph below.
Sholpan [36]
It’s the one that is horizontal (side ways )
5 0
3 years ago
Read 2 more answers
A line passes through the point (6, -1) and has a slope of 3/2 Write an equation in slope-intercept form
Luda [366]

9514 1404 393

Answer:

  y = 3/2x -10

Step-by-step explanation:

The point-slope equation can be written ...

  y = m(x -h) +k . . . . . for a line with slope m through point (h, k)

Using the given values, this is ...

  y = (3/2)(x -6) -1 = 3/2x -9 -1

  y = 3/2x -10 . . . . . slope-intercept equation

6 0
3 years ago
The sides of a square are all increased by 3 cm. The area of the new square is 64 cm'.
brilliants [131]

Side of the original square is 5 cm.

Step-by-step explanation:

  • Step 1: Let the side of the original square be x. Then side of the new square = x + 3 and Area of new square = 64 cm²

Area of a square = (side)²

⇒ 64 = (x + 3)²

⇒ 64 = x² + 6x + 9

⇒ x² + 6x - 55 = 0

⇒ x² + 11x - 5x - 55 = 0        (Since 6x = 11x - 5x as part of factorizing)

⇒ x(x + 11) - 5(x + 11) = 0

⇒ (x + 11)(x - 5) = 0

⇒ x = -11 and x = 5 (Lengths can't be negative)

Side of the original square is 5 cm.

4 0
2 years ago
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