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NeX [460]
3 years ago
12

Clearing fractions SOLVE

Mathematics
1 answer:
lana66690 [7]3 years ago
4 0
You can multiply by -30 to clear fractions.
.. 47 ≤ 10x +60

Now, subtract 60 and divide by 10
.. -13 ≤ 10x
.. -1.3 ≤ x

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Which state has the least school districts per capita?
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The median of a continuous random variable having distribution function F is that value m such that F(m) = 1/2 . That is, a rand
neonofarm [45]

Answer:

Step-by-step explanation:

To find median and mode for

a) In a uniform distribution median would be

(a+b)/2 and mode = any value

b) X is N

we know that in a normal bell shaped curve, mean = median = mode

Hence mode = median = \mu

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7 0
3 years ago
What is the area, in square inches, of the isosceles trapezoid below?
Komok [63]
A = 73.84

Explanation-

14.2 - 6.4 = 7.8 (to get the length of the base without the top part)

7.8 • 5.2 = 40.56 (to find the area outside of our subtracted square that has the top part)

6.4 • 5.2 = 33.28 (to find the area of the inner square)

40.56 + 33.28 = 73.84 (adding together both parts to find the total area)

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7 0
3 years ago
Give two different sequences of three transformations that would map PQR onto EFG given that PQR=EFG.
Gre4nikov [31]

9514 1404 393

Answer:

  1. Translate P to E; rotate ∆PQR about E until Q is coincident with F; reflect ∆PQR across EF
  2. Reflect ∆PQR across line PR; translate R to G; rotate ∆PQR about G until P is coincident with E

Step-by-step explanation:

The orientations of the triangles are opposite, so a reflection is involved. The various segments are not at right angles to each other, so a rotation other than some multiple of 90° is involved. A translation is needed in order to align the vertices on top of one another.

The rotation is more easily defined if one of the ∆PQR vertices is already on top of its corresponding ∆EFG vertex, so that translation should precede the rotation. The reflection can come anywhere in the sequence.

__

<em>Additional comment</em>

The mapping can be done in two transformations: translate a ∆PQR vertex to its corresponding ∆EFG point; reflect across the line that bisects the angle made at that vertex by corresponding sides.

3 0
2 years ago
Read 2 more answers
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