Answer:
q = 16
Step-by-step explanation:
3(q - 7) = 27
3q - 21 = 27
3q = 27 + 21
3q = 48
q = 48/3
q = 16
Answer:
x = 28 m
y = 14 m
A(max) = 392 m²
Step-by-step explanation:
Rectangular garden A (r ) = x * y
Let´s call x the side of the rectangle to be constructed with a rock wall, then only one x side of the rectangle will be fencing with wire.
the perimeter of the rectangle is p = 2*x + 2*y ( but in this particular case only one side x will be fencing with wire
56 = x + 2*y 56 - 2*y = x
A(r) = ( 56 - 2*y ) * y
A(y ) = 56*y - 2*y²
Tacking derivatives on both sides of the equation we get:
A´(y ) = 56 - 4 * y A´(y) = 0 56 - 4*y = 0 4*y = 56
y = 14 m
and x = 56 - 2*y = 56 - 28 = 28 m
Then dimensions of the garden:
x = 28 m
y = 14 m
A(max) = 392 m²
How do we know that the area we found is a local maximum??
We find the second derivative
A´´(y) = - 4 A´´(y) < 0 then the function A(y) has a local maximum at y = 14 m
Step-by-step explanation:
1/2 b×h that's the area
The answer is 7 square units
2-1+1*5= 6
just follow pemdas and simplify
Here,
In Right angle triangle,
base = 12 m
height = 8 m
Now,
◇ Area = 1/2*b*h
= 1/2*12*8
= 48 m^2
In semicircle,
radius = 4 m
Then,
◇Area" = 1/2*22/7*r^
= 1/2*22/7*4*4
= 25.14m^2
Again,
◆Total Area = Right triangle + semicircle
= (48+25.14) m^2
= 73.14 m^2
This is right answer...
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