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3 years ago

Hy! (√2+1)²+(3-√3)²-(√5+1)²=??? Thank yours!:*

1 answer:

4 0

$(\sqrt2+1)^2+(3-\sqrt3)^2-(\sqrt5+1)^2=\\
2+2\sqrt2+9-6\sqrt3+9-(5+2\sqrt5+1)=\\
20+2\sqrt2-6\sqrt3-5-2\sqrt5-1=\\
14+2\sqrt2-6\sqrt3-2\sqrt5$

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Help please!

Anna71 [15]

Answer:

y= -4x^2 + 15x - 14

Step-by-step explanation:

A parabola is always in the form y = ax^2 + bx + c.

Substitute each point to produce different equations:

-14 = 0a + 0b + c = c

so c = -14

-3 = a1^2 + b1 + c = a + b - 14

so a + b = 11

0 = a2^2 + b2 + c = 4a + 2b -14 = 0

so 4a + 2b = 14

if we double a + b = 11 we get 2a + 2b = 22

Subtract this from 4a + 2b = 14 and we get 2a = -8 so a= -4 and b = 11 - a = 15

We don't need to use the (3,5) points as we have all the information we need.

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3 years ago

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Your plan was to be on the road by 9 A.M. but you did not leave the garage until 10 A.M. You then drove with the cruise control

Wittaler [7]

Answer:

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

Step-by-step explanation:

The average speed is given by the following equation:

$v = \frac{d}{t}$

From 10A.M. to noon.

You traveled at 50mph during 2 hours. So how long you traveled?

$50 = \frac{d}{2}$

$d = 50*2$

$d = 100$

You traveled 100 miles.

What was your average speed over the time interval from 9 A.M. to noon

From 9 A.M. to 10 A.M, you did not travel.

From 10 P.M. to noon, 100 miles.

So 100 miles during 3 hours.

$v = \frac{d}{t} = \frac{100}{3} = 33.33$

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

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3 years ago

Solve for x in quadratic equation if x(2x-1)=1 , can you please help me please

kumpel [21]

Answer:

x=1 or -1/2

Step-by-step explanation:

The value of x is 1 or -1/2

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3 years ago

The graph shows the total number of inches of snow after different numbers of hours.

erastova [34]

Answer:

A, is the answer.

Step-by-step explanation:

If you take two points and then find the slope between them you'll find that it is 1.5.

You could also make a T-chart or plug in the x coordinates into each possible equation and see which one matches the corresponding y coordinate.

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2 years ago

Find the area of the semicircle. diameter = 12

dimaraw [331]

Answer:

$\huge\boxed{\sf Area\ of \ Semicircle = 56.55 \ units^2}$

Step-by-step explanation:

Diameter = 12

Radius = 12/2 = 6

$\sf Area\ of \ Semicircle =\frac{\pi r^2}{2} \\Area\ of \ Semicircle =\frac{\pi (6)^2}{2} \\Area \ of \ Semicircle = \frac{\pi (36)}{2}\\ Area \ of \ Semicircle = 18 \ pi$

$\sf Area\ of \ Semicircle = 56.55 \ units^2$

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3 years ago

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