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julsineya [31]
3 years ago
9

Hy! (√2+1)²+(3-√3)²-(√5+1)²=??? Thank yours!:*

Mathematics
1 answer:
OlgaM077 [116]3 years ago
4 0
(\sqrt2+1)^2+(3-\sqrt3)^2-(\sqrt5+1)^2=\\
2+2\sqrt2+9-6\sqrt3+9-(5+2\sqrt5+1)=\\
20+2\sqrt2-6\sqrt3-5-2\sqrt5-1=\\
14+2\sqrt2-6\sqrt3-2\sqrt5
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Answer:

D'(-2, 2); C''(3, -1); A'''(4, -2); and B''(4, 2)

Step-by-step explanation:

See attachment for the figure.

<u>For D'</u>, rotating the point (2, 2) 90° counterclockwise. This maps each point (x, y)→(-y, x); it takes (2, 2)→(-2, 2).  

For C'', rotating the point (1, 3) 90° clockwise.  This maps each point (x, y)→(y, -x); it takes (1, 3)→(3, -1).

For A''', rotating the point (-4, 2) 180° clockwise.  This maps every point (x, y)→(-x, -y); it takes (-4, 2)→(4, -2).

For B'', rotating the point (-2, 4) 270° counterclockwise.  This is the similar as rotating the point 90° clockwise.  This maps every point (x, y)→(y, -x); it takes (-2, 4)→(4, 2).

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