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julsineya [31]
3 years ago
9

Hy! (√2+1)²+(3-√3)²-(√5+1)²=??? Thank yours!:*

Mathematics
1 answer:
OlgaM077 [116]3 years ago
4 0
(\sqrt2+1)^2+(3-\sqrt3)^2-(\sqrt5+1)^2=\\
2+2\sqrt2+9-6\sqrt3+9-(5+2\sqrt5+1)=\\
20+2\sqrt2-6\sqrt3-5-2\sqrt5-1=\\
14+2\sqrt2-6\sqrt3-2\sqrt5
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Logarithmic functions and exponential functions are inverse and opposite of one another

The logarithmic function is y = \log_2(x), and the length at 8 pascals is 3 units

<h3>How to determine the logarithmic function</h3>

The exponential function is given as:

f(x) = 2^x

Express f(x) as y

y = 2^x

Swap the positions of x and y

x = 2^y

Take the logarithm of both sides

\log(x) = \log(2^y)

Apply the rule of logarithm

\log(x) = y\log(2)

Divide both sides by log(2)

y = \frac{\log(x)}{\log(2)}

Apply the change of base rule of logarithm

y = \log_2(x)

When the strength is 8 pascals, we have:

y = \log_2(8)

Express 8 as 2^3

y = \log_2(2^3)

So, we have:

y =3 \log_2(2)

Evaluate log 2 base 2

y =3

Hence, the logarithmic function is y = \log_2(x), and the length at 8 pascals is 3 units

Read more about logarithmic and exponential functions at:

brainly.com/question/11464095

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The van will need 25 gallons of gas to go 500 miles.

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