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Irina-Kira [14]
3 years ago
9

If question 7, how do you solve for the angles

Mathematics
1 answer:
ladessa [460]3 years ago
8 0
ABC is same as FDE
so AC = FE  = 5ft
angle B = 28 deg
angle C = 90 deg
so A = 180 - B - C = 62

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Find sin theta if theta is an angle in standard position and the point with coordinates (3, -4) lies on the terminal side of an
alisha [4.7K]

Answer:

\sin \theta=-\frac{4}{5}

Step-by-step explanation:

Given:

Angle is in standard position which means the starting ray is at the origin. The terminal side has coordinates (3, -4).

So, the 'x' value is 3 and 'y' value id -4.

Using Pythagoras Theorem, we find the hypotenuse.

Hypotenuse = \sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5

Now, using the sine ratio for the angle, we have

\sin \theta=\frac{Opposite}{Hypotenuse}\\\sin \theta=\frac{-4}{5}\\\sin \theta=-\frac{4}{5}

Therefore, the value of \sin \theta is -\frac{4}{5}.

The value is negative as the point (3, -4) lies in the fourth quadrant and sine ratio is negative in the fourth quadrant,

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3 years ago
a student carres a bag weighing 5kg from the ground floor to his clas on the first floor that is 2m high. the work done by the b
Studentka2010 [4]
The answer is: C 100 J
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2 years ago
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Use the formula h=16t2, where t is time in seconds and h is the distance in feet traveled by a free-falling body or object to so
aksik [14]

Answer:

The time required is 15.97 second.

Step-by-step explanation:

Consider the provided information.

A skywalk is 90 feet beyond the canyon's edge and is 4080 ft above the canyon floor.

First find the distance between skywalk and canyon floor by using Pythagorean theorem.

Distance between skywalk and canyon's edge = \sqrt{4080^2+90^2}

Distance between skywalk and canyon's edge = 4080.99

Substitute h = 4080.99 in the provided formula.

4080.99=16t^2

t^2=255.062

t=15.97

Hence, the time required is 15.97 second.

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3 years ago
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27/40

Step-by-step explanation:

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I got this wrong I need help please
statuscvo [17]
<h3>Answer: Choice A) </h3>

No, the piecewise graph is NOT a function because it does NOT pass the vertical line test.

The vertical line test is where we try to pass a line through more than one point on the curve. If it is not possible to do this, then the graph is said to "pass the vertical line test".

In this case, the given graph fails the vertical line test. Look at something like x = -2. We can draw a vertical line through here to pass through more than one point. One point is on the upside-down V shape, and the other point is on the parabolic shape. Plugging x = -2 into this leads to more than one y outputs.

A function is only possible if any valid x input (from the domain) leads to exactly one output y value (in the range).

8 0
3 years ago
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