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Lelu [443]
3 years ago
11

Which one is cheaper and why

Mathematics
1 answer:
Shtirlitz [24]3 years ago
5 0

Hey there! :)

Answer:

The bag is cheaper because one litre is roughly $1.00, compared to the carton which is $1.99 for one litre.

Step-by-step explanation:

Given:

Bag of 4 litre milk = $3.99

Carton of 1 litre milk = $1.99

Find the price per litre for a bag of milk:

\frac{3.99}{4} = \frac{x}{1}

Cross multiply:

3.99 = 4x

Divide both sides by 4:

3.99/4 = x.

x = 0.9975 ≈ $1.00

Bag of 1 litre milk ≈ $1.00

Carton of 1 litre milk = $1.99

$1.00 < $1.99

Therefore, the bag is cheaper.

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Macy’s is having a sale in which all jeans at $30. The sales tax is 8%. If John buys n pairs of jeans during this sale, the tota
Amiraneli [1.4K]

This expression is correct. It shows the price John pays for the jeans on the left side of the + symbol (30n), and the amount of tax he has to pay on the right side of the symbol (0.08(30n)).

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3 0
3 years ago
Use the law of cosines to find the length of side C.
sergij07 [2.7K]

Answer:

\text{D. 36.64}

Step-by-step explanation:

The Law of Sines is given by \frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C} and works for any triangle.

Therefore, we have the proportion:

\frac{c}{\sin 41.5^{\circ}}=\frac{37}{\sin 42^{\circ}},\\\\c=\frac{37\sin 41.5^{\circ}}{\sin 42^{\circ}}=36.6399945706\approx \boxed{36.64}

8 0
3 years ago
What is 12 and 13 please help
Tanzania [10]
12. 1500 cm² 
13. Monica forgot to multiply by 1/2 
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5 0
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Please anyoneeeeeeee.....i am almost done just please help me
Vitek1552 [10]

\boxed{\sf \overrightarrow{XV}\:and\:\overrightarrow{XY}}

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7 0
3 years ago
The table gives estimates of the world population, in millions, from 1750 to 2000. (Round your answers to the nearest million.)
BaLLatris [955]

Answer:

A.) 1508 ; 1870

B.) 2083

C.) 3972

Step-by-step explanation:

General form of an exponential model :

A = A0e^rt

A0 = initial population

A = final population

r = growth rate ; t = time

1)

Using the year 1750 and 1800

Time, t = 1800 - 1750 = 50 years

Initial population = 790

Final population = 980

Let's obtain the growth rate :

980 = 790e^50r

980/790 = e^50r

Take the In of both sides

In(980/790) = 50r

0.2155196 = 50r

r = 0.2155196/50

r = 0.0043103

Using this rate, let predict the population in 1900

t = 1900 - 1750 = 150 years

A = 790e^150*0.0043103

A = 790e^0.6465588

A = 1508.0788 ; 1508 million people

In 1950;

t = 1950 - 1750 = 200

A = 790e^200*0.0043103

A = 790e^0.86206

A = 1870.7467 ; 1870 million people

2.)

Exponential model. For 1800 and 1850

Initial, 1800 = 980

Final, 1850 = 1260

t = 1850 - 1800 = 50

Using the exponential format ; we can obtain the rate :

1260 = 980e^50r

1260/980 = e^50r

Take the In of both sides

In(1260/980) = 50r

0.2513144 = 50r

r = 0.2513144/50

r = 0.0050262

Using the model ; The predicted population in 1950;

In 1950;

t = 1950 - 1800 = 150

A = 980e^150*0.0050262

A = 980e^0.7539432

A = 2082.8571 ; 2083 million people

3.)

1900 1650

1950 2560

t = 1900 - 1950 = 50

Using the exponential format ; we can obtain the rate :

2560 = 1650e^50r

2560/1650 = e^50r

Take the In of both sides

In(2560/1650) = 50r

0.4392319 = 50r

r = 0.4392319/50

r = 0.0087846

Using the model ; The predicted population in 2000;

In 2000;

t = 2000 - 1900 = 100

A = 1650e^100*0.0087846

A = 1650e^0.8784639

A = 3971.8787 ; 3972 million people

3 0
3 years ago
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