Match the exponential expression on the left with the equivalent, simplified expression on the right

The circumference of the hub cap of a tire is 83.96 centimeters. Find the area of this hub cap. Use 3.14 for . Use pencil and pa

Bess [88]

Answer:

Area = $561.2485$ square centimeter

If the circumference of the hub cap would have been smaller, then its radius would have been smaller and subsequently its area would also have been less.

Step-by-step explanation:

As we know the circumference of a circle is $2\pi r$

The radius of the hub cap needs to be devised to determine the area

$83.96$ $= 2* 3.14*r$

$r = \frac{83.96}{2*3.14}$

$r = 13.37$ centimeters

Area of the hub cap = $\pi r^{2}$

Substituting the devised value of r in the above equation, we get -

$3.14 * 13.37^2\\$

$561.2485$ square centimeter

If the circumference of the hub cap would have been smaller, then its radius would have been smaller and subsequently its area would also have been less.

5 0

3 years ago

Solve these two equations using the Addition Method (also known as the elimination method).

Brums [2.3K]

Answer:

(-2, 3)

Step-by-step explanation:

5/2(3/4x + 1/3y = -1/2)

1/2x - 5/6y = -7/2

15/8x + 5/6y = -5/4

19/8x = -19/4

x = -2

1/2(-2) - 5/6y = -7/2

-1 -5/6y = -7/2

-5/6y = -5/2

y = 3

4 0

3 years ago

INCREDIBLY URGENT!

klemol [59]

Answer:

a) By graphing just one interval of length $T$ . b) Infinite number of angles, c) Infinite times.

Step-by-step explanation:

Any function is periodical when:

$f(t) = f(t+i\cdot T)$ , $\forall i \in \mathbb{N}_{O}$

Where $T$ is the period of the function. The periodicity of the function allows us to limit the graphing of the function to just an interval of one period and according to the definition, you can expect same output with n different angles (infinite number of angles and same output infinite times).

4 0

3 years ago

PLZ HELP 15 POINTS

Hatshy [7]

Answer:

see attached

Step-by-step explanation:

It's almost easier for you to do this than it is to post a question on Brainly.

All you need to do is type the relevant expressions. Once you have Desmos show you the vertex, writing the x= equation for that is all that is required to draw it.

6 0

3 years ago

Can yall help me out

Nastasia [14]

Answer:

Question 1 (1 point)

1. An object has a mass of 25g and a volume of 5ml

a

10

b

8

c

5

d

7

Question 2 (1 point)

2. An object has a mass of 30g and a volume of15ml. What is the density?

a

10

b

2

c

3

d

5

Question 3 (1 point)

3. An object has a mass of 200g and a volume of 100ml. What is the density?

a

2

b

4

c

6

d

8

Question 4 (1 point)

4. An object has a mass of 17g and a volume of 2ml. What is the density?

a

2.4

b

2

c

8

d

8.5

Question 5 (1 point)

5. An object has a mass of 20g and a volume of 5ml. What is the density?

a

2

b

4

c

10

d

2.5

Question 6 (1 point)

6. An object has a mass of 75g and a volume of 75ml. What is the density?

a

6

b

1

c

7

d

8

Question 7 (1 point)

7. An object has a volume of 100ml and a mass of 2oo ml. What is the density?

a

0.5

b

1

c

4

d

2.5

Question 8 (1 point)

8. An object has a volume of 5ml and a mass of 650 g. What is the density?

a

110

b

120

c

130

d

200

Question 9 (1 point)

9. An object has a mass of 15g and a volume of 5ml. What is the density?

a

2.5

b

7

c

3

d

2.56

Question 10 (1 point)

10. An object has a mass of 13g and a volume of 2ml. What is the density?

a

6.5

b

3.7

c

4

d

Step-by-step explanation:

7 0

3 years ago