Answer:
a= 40-3b-c/5
a=-10+3b-2c
a=50+2b-3c/14
Step-by-step explanation:
5a+3b+c-(3b+c)=40-(3b+c)
5a=40-3b-c
5a/5=40/5-3b/5-c/5
a= 40-3b-c/5
a-3b+2c-(3b+2c)=-10-(-3b+2c)
a=-10+3b-2c
14a-2b+3c-(-2b+3c)=50-(-2b+3c)
14a=50+2b-3c
14a/14=50/14+2b/14-3c/14
a=50+2b-3c/14
Y = 2x + 2
Y = 2x -
Subtract
0 = 2
This makes no sense meaning the lines are parallel. Therefore there are 0 solutions.
Answer:
Given:
The distances, in yards, that a team moves on its first five plays are 2, 21, 4, 3, and 25.
Solved:
1. The greatest number is 25
2. If the moved distances are square, which one is largest?
3. The move which is greater than 4 is considered "big play"
=> 21 and 25 are big play (21 > 4, 25 > 4)
Hope this helps!
:)
