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Rasek [7]
3 years ago
11

Negative 3 plus negative 17 minus negative 13

Mathematics
2 answers:
OlgaM077 [116]3 years ago
7 0

Answer:

-7

Step-by-step explanation:

(-3) + (-17) = (-20)

(-20) - (13) = (-7)

This is all because when adding a negative with a negative, it's like adding normally with positives but with a negative answer at the end. For example we would have (-3) + (-5). I would just add these normally (3 + 5)=8 and then add a negative at the end. Same sequence with subtracting.

azamat3 years ago
5 0
It would be -7 hope this helps

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If the parallelogram is reflected across the x-axis, what are the coordinates of point B after the reflection? Please hurryyyy‼️
Wittaler [7]

Answer:

(5,-1)

Step-by-step explanation:

when reflecting over the x-axis:

(x,y) → (x,−y)

get coordinates of D: (5,1)

get coordinates of D': (5,-1)

hope this helped!

4 0
3 years ago
Pls help and show workings due ASAP
Gennadij [26K]

Answer:

m = 2/3

Step-by-step explanation:

slope is equal to rise/run

rise = y2 - y1 = 7 - 1 = 6

run = x2 - x1 = 3 - (-6) = 9

simplify 6/9 = 2/3

7 0
3 years ago
Daniel rollerbladed 3 miles in 12 minutes. At this rate, how many miles will he rollerblade in 1 hour? Show your work.
Yakvenalex [24]

Answer:

Daniel is rollerblading at 15 miles per hour

Daniel can go 3 miles in 12 minutes so we do 12÷3 to find out how many minutes it takes to go 1 mile which is 4 now we do 60÷4 to get 15

Alternatively we could do 60÷12 to get 5 then do 3×5 to get 15

Step-by-step explanation:

3 0
3 years ago
Find the area of the parallelogram. (simplify your answer)
Sophie [7]
A = b . h
a = 13 . 7
a = 91 cm^2
3 0
3 years ago
EASY BRAINLIEST PLEASE HELP!!
butalik [34]

Answer:

see below

Step-by-step explanation:

<h3>Proposition:</h3>

Let the diagonals AC and BD of the Parallelogram ABCD intercept at E. It is required to prove AE=CE and DE=BE

<h3>Proof:</h3>

1)The lines AD and BC are parallel and AC their transversal therefore,

\displaystyle  \angle DAC =  \angle ACB \\  \ \qquad [\text{ alternate angles theorem}]

2)The lines AB and DC are parallel and BD their transversal therefore,

\displaystyle  \angle BD C=  \angle ABD \\  \ \qquad [\text{ alternate angles theorem}]

3)now in triangle ∆AEB and ∆CED

  • \displaystyle \angle EAD=\angle ECB
  • \angle EDA=\angle EBC
  • \displaystyle AD=BC

therefore,

\displaystyle  \Delta AEB  \cong  \Delta CED

hence,

  • AE=CE
  • DE=BE

Proven

6 0
3 years ago
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