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3 years ago

5

Can someone help me out

1 answer:

Nastasia [14]3 years ago

4 0

Answer:

1) -6/-10=3/5

2) -27/10x75/18 = -2025/180 = -135/12 (or) -11 1/4 (or) -11.25

3) 7+8-9=6

4) Billions

5) No, because you can't take a negative number of classes

Step-by-step explanation:

1) -6/-10=3/5

2) -27/10x75/18 = -2025/180 = -135/12 (or) -11 1/4 (or) -11.25

3) 7+8-9=6

4) Billions

5) No, because you can't take a negative number of classes

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3 years ago

Adam has $21 to spend on three pencils. After buying them he had $9. How much did each pencil cost?

Mice21 [21]

Answer:

Each Pencil Cost 4 Dollars

Step-by-step explanation:

First you can subtract 21 by 9 to get 12 dollars which shows how much he spent.

Second you can divide 12 by 3 to get 4 dollars spent. So he spent 4 dollars on each pencil.

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3 years ago

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2 years ago

A.) pinky bought 1 1/2 kg of apples and 5 1/4 kg of mangoes and 1 1/2 Kg of oranges. Find the total weight of fruits B.) If her

Natasha2012 [34]

Answer:

a) The total weight of fruits is $8\,\frac{1}{4}$ kilograms, b) The weight of the fruits left is $4\,\frac{1}{2}$ kilograms.

Step-by-step explanation:

a) The total weight of fruits ( $m_{T}$ ) is calculated by the following formula:

$m_{T} = m_{a} + m_{m}+m_{o}$

Where:

$m_{a}$ - Total weight of apples, measured in kilograms.

$m_{m}$ - Total weight of mangoes, measured in kilograms.

$m_{o}$ - Total weight of oranges, measured in kilograms.

If $m_{a} = 1\,\frac{1}{2} \,kg$ , $m_{m} = 5\,\frac{1}{4}\,kg$ and $m_{o} = 1\,\frac{1}{2}\,kg$ , then:

$m_{T} = 1\,\frac{1}{2}\,kg + 5\,\frac{1}{4}\,kg + 1\,\frac{1}{2}\,kg$

$m_{T} = \frac{6}{4}\,kg + \frac{21}{4}\,kg + \frac{6}{4}\,kg$

$m_{T} = \frac{33}{4}\,kg$

$m_{T} = 8\,\frac{1}{4}\,kg$

The total weight of fruits is $8\,\frac{1}{4}$ kilograms.

b) The weight eaten by her family is determined by the following expression:

$m_{E} = m_{a,e} + m_{m,e} + m_{o,e}$

Where:

$m_{a,e}$ - Eaten weight of apples, measured in kilograms.

$m_{m,e}$ - Eaten weight of mangoes, measured in kilograms.

$m_{o,e}$ - Eaten weight of oranges, measured in kilograms.

Given that $m_{a,e} = \frac{3}{4}\,kg$ , $m_{m,e} = 2\,\frac{1}{2}\,kg$ and $m_{o,e} = \frac{1}{2}\,kg$ , the weight eaten by her family is:

$m_{E} = \frac{3}{4}\,kg + 2\,\frac{1}{2}\,kg + \frac{1}{2}\,kg$

$m_{E} = \frac{3}{4}\,kg + \frac{10}{4}\,kg + \frac{2}{4}\,kg$

$m_{E} = \frac{15}{4}\,kg$

$m_{E} = 3\,\frac{3}{4}\,kg$

The weight of the fruits left is found by subtraction:

$m_{R} = m_{T}-m_{E}$

$m_{R} = 8\,\frac{1}{4} \,kg -3\,\frac{3}{4}\,kg$

$m_{R} = \frac{33}{4}\,kg-\frac{15}{4}\,kg$

$m_{R} = \frac{18}{4}\,kg$

$m_{R} = 4 \,\frac{1}{2}\,kg$

The weight of the fruits left is $4\,\frac{1}{2}$ kilograms.

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3 years ago

15p!!what is the percent of change from 86 to 77? round to the nearest percent!

kozerog [31]

Answer:

10%

Step-by-step explanation:

The difference between 86 and 77 is 9.

Divide 9 by 86

$\frac{9}{86} = .1046511$

Multiply by 100

$.1046511 * 100 = 10.46511$

Round to the nearest percent

$10.46511 \rightarrow 10 \textrm{ percent}$

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3 years ago