You have to get rid of 1/2 by multiplying it by its recriprocal which is like this:
1) 1/2 x 2/1 which equals to zero and you do the same to the other side.
2) -12 x 2/1 = -24x then multiply-24x with 7 which equals -168.
16-x= -24x -168
3) subtract 16 to the other side and subtract 24x with x
23x= -184
4) divide by 23 to isolate x and you get -8
5) x=-8

6 0

3 years ago

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For any two integers x and y, |x + y| = |x| + |y|. _ is this true or false if false provide counterclaim

Klio2033 [76]

False.

Let x = -1 and y = 1. Then x + y = 0, so that

|x + y| = |0| = 0

but

|x| = |-1| = 1

|y| = |1| = 1

|x| + |y| = 1 + 1 = 2

7 0

2 years ago

50 points help Which number is a common factor of 24 and 136?

Tom [10]

Answer:

1, 2, 4, 8. 8 is the greatest common factor.

Step-by-step explanation:

Find factors of both.

24: 1, 2, 3, 4, 6, 8, 12, 24

136: 1, 2, 4, 8, 17, 34, 68, 136

Find common numbers.

24: 1, 2, 3, 4, 6, 8, 12, 24

136: 1, 2, 4, 8, 17, 34, 68, 136

Factors are 1, 2, 4, and 8.

5 0

3 years ago

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Which of the following are trigonometric identities? check all that apply.(Need help asap)

dybincka [34]

A. Yes:

$\dfrac{\sin(x+y)}{\sin x\cos y}=\dfrac{\sin x\cos y+\cos x\sin y}{\sin x\cos y}=1+\cot x\tan y$

B. Yes:

$\dfrac{\csc x-\sin x}{\csc x}=1-\dfrac{\sin x}{\frac1{\sin x}}=1-\sin^2x=\cos^2x$

C. Yes:

$\tan x\cos x\csc x=\dfrac{\sin x}{\cos x}\cdot\cos x\cdot\dfrac1{\sin x}=1$

D. No: if $x=0$ , then $4\cos0\sin0=0$ , but $2\cos0+1-2\sin0=3$ .

7 0

3 years ago

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