1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vladimir1956 [14]
3 years ago
15

What is the value of the expression?

Mathematics
1 answer:
Kamila [148]3 years ago
7 0
Must do multiplication first....
-2/5 - 3/7 x 7/10
-2/5 - 21/70 (I'll reduce 21/70)
-2/5 - 3/10
Now you have to find a common denominator and subtract
-35/50 = -7/10......is what I get
You might be interested in
(5x - 1, if x &lt; -2<br> Evaluate f(x) =<br> Lx+ 3, if x &gt; -2<br> when z = 3.
Brilliant_brown [7]

Answer:

(5x - 1, if x < -2

Evaluate f(x) =

Lx+ 3, if x > -2

when z = 3.

Step-by-step explanation:

5 0
2 years ago
Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.
lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ

Likewise:

\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

m\angle PAC=m\angle PAB+m\angle BAC

Likewise:

m\angle QAB=m\angle QAC+m\angle BAC

Since ∠QAC ≅ ∠PAB:

m\angle PAC=m\angle QAC+m\angle BAC

And by substitution:

m\angle PAC=m\angle QAB

Thus:

\angle PAC\cong \angle QAB

Then by SAS Congruence:

\Delta PAC\cong \Delta BAQ

And by CPCTC:

PC\cong BQ

5 0
3 years ago
Read 2 more answers
Halle solved 664/48 below. She got a quotient of 13 with a remainder of 40. How could she solve 659/48 without redoing the work?
Lerok [7]
She should multiply the quotient by 48.
3 0
3 years ago
What should you do first in solving the quadratic equation?<br> x² + 18x + 81 = 25
N76 [4]

Answer:

x= -4,-14

Step-by-step explanation:

Try first to solve the equation by factoring. Be sure that your equation is in standard form before you start your factoring attempt.

3 0
3 years ago
Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
jeka94

Answer:

  • 892 lb (right)
  • 653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

  Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

     = 800sin(75°)/sin(120°) ≈ 892 . . . pounds

  L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

  (right, left) = w/sin(α+β)×(sin(β), sin(α))

5 0
3 years ago
Other questions:
  • X+y=5 3x+3y=10 eliminacion
    7·1 answer
  • Julie needs to cut 4 pieces of yarn, each with the same length, and a piece of yarn 7.75 inches long. Let x represent the length
    7·2 answers
  • Show all your work plz help now
    15·1 answer
  • Which graph represents polynomials function f(x)=x^3+4x^2-15x-18
    9·2 answers
  • Investors buy a studio apartment
    15·1 answer
  • Which inequality is true?
    10·1 answer
  • Hey! i’ll give brainliest please help
    5·2 answers
  • Lidocaine (2 grams) was prescribed in 500 mL of fluid at 2 mg/ minute, to be administered via an infusion pump. What is the flow
    9·1 answer
  • In a teacher's math course, a linear regression line was calculated to predict
    14·1 answer
  • Suppose that in a random sample of 240 smartphone users, 160 used an iPhone. Conduct a hypothesis test at significance level 0.0
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!