Answer:
IQ scores of at least 130.81 are identified with the upper 2%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 100 and a standard deviation of 15.
This means that
What IQ score is identified with the upper 2%?
IQ scores of at least the 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.
IQ scores of at least 130.81 are identified with the upper 2%.
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Answer:
7.71
Step-by-step explanation:
The diameter is 3, so the arc length is 180/360 * 3pi or 3pi/2. Now you add the 3 in the base, so it is 3pi/2 + 3 or approximately 7.71 (I used a calculator for that).
Your answer to this is:
0.2
Answer:
4.2 cubic inches
Step-by-step explanation:
Find the diagram attached
Volume of the rectangular pyramid = BH/3
B is the base area
H is the height of the pyramid
Given
Base area = 3.2in * 1.4in
Base area = 4.48sq. in
Height = 2.8in
Volume of the rectangular pyramid = 4.48*2.8/3
Volume of the rectangular pyramid = 12.544/3
Volume of the rectangular pyramid = 4.2 cubic inches