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ivann1987 [24]
3 years ago
5

Solve by Elimination 2x+5y=9 3x-5y=11

Mathematics
2 answers:
shepuryov [24]3 years ago
8 0

Answer:

x = 4 , y = ⅕

Step-by-step explanation:

2x + 5y = 9 (1)

3x - 5y = 11 (2)

Add (1) and (2)

5x = 20

x = 4

Using (1), find y

2(4) + 5y = 9

5y = 1

y = ⅕

natulia [17]3 years ago
7 0
The systems of equations would be (4,1/5)

These equations can be solved much easier because they are already set up for you!

First you want to add both of the equations up and get it to where only one x or y value is available. So as you can see -5y and 5y cancel out and the leaves you with the added up equation as 5x=20. Next you want to isolate x by dividing by 5 on both sides to get x=4

Now that you have what x equals you want to plug it in one equation (or both if you really want to check if the answer is correct). Let’s use the first equation and plug 4 for x. 2(4)+5y=9 next simplify and you’ll get 8+5y=9 and now subtract 8 on both sides to get 5y by itself so you get 5y=1. Isolate y by dividing 5 on both sides and you’ll get y=1/5. Your systems of equations would equal (4,1/5).
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Can someone help answer this question Ive tried a lot and couldnt do it.
aleksklad [387]

Answer:

1222

Step-by-step explanation:

You have a triangular prism on top of a rectangular prism.  The surface area is the sum of the areas of the exposed faces.

Starting with the triangular prism, the surface area is the area of the two triangular bases plus the area of the two rectangular sides (the bottom rectangular face is ignored).

A = ½ (10) (12) + ½ (10) (12) + (13) (9) + (13) (9)

A = 60 + 60 + 117 + 117

A = 354

The surface area of the rectangular prism is the area of the two rectangular bases (front and back), plus the two walls (left and right), plus the bottom, plus the top (minus the intersection with the top prism).

A = (19) (11) + (19) (11) + (9) (11) + (9) (11) + (19) (9) + (19) (9) − (10) (9)

A = 209 + 209 + 99 + 99 + 171 + 171 − 90

A = 868

So the total surface area is:

354 + 868

1222

5 0
3 years ago
Which triangles could not be similar to triangle ABC ? triangle a b c with right angle b. side a b is 12 cm. side b c is 5 cm. s
Vera_Pavlovna [14]

Answer:

triangle JKL

Step-by-step explanation:

This is because the lengths of each side JKL is a factor to ABC

respectively .

AB=12,JK=36

AC=13,JL=39

BC=5,KL=25

I hope you understand

6 0
2 years ago
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lana66690 [7]
N= -16.5

Subtract 33 then divide by 2
2n=-33
n=-33/2 or n=-16.5
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