All categories

2 years ago

In the diagram a set of parallel lines are cut by a transversal.

Mathematics

2 answers:

kifflom [539]2 years ago

3 0

Answer:

C. Angle 3 and 4 are vertical angles

saw5 [17]2 years ago

3 0

Answer:

D. Angles 4 and 5 are alternate interior angles.

Step-by-step explanation:

You might be interested in

Have y'all ever experienced Deja Vu before?

anygoal [31]

Answer:

yea i have its kinda crazy

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the input (x) of the function y=5x-3 if the output (y) is 32

Alborosie

Answer:

x = 7

Step-by-step explanation:

Given

y = 5x - 3 ← equate 5x - 3 to 32

5x - 3 = 32 ( add 3 to both sides )

5x = 35 ( divide both sides by 5 )

x = 7 ← input

3 0

3 years ago

Read 2 more answers

Slove this equation<br>28 /3

Snowcat [4.5K]

Answer:

Step-by-step explanation:

so u divide 28 by 3 and u get 9 but u have 1 left but if you keep dividing u will get 3 so its 9.33 into infinty

3 0

3 years ago

Save me the headache

maxonik [38]

$(9\sin2x+9\cos2x)^2=81$

Taking the square root of both sides gives two possible cases,

$9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1$

$9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1$

Recall that

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

If $\alpha=2x$ and $\beta=\dfrac\pi4$ , we have

$\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}$

so in the equations above, we can write

$\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1$

Then in the first case,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi$

(where $n$ is any integer)

$\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi$

$\implies x=n\pi\text{ or }\dfrac\pi4+n\pi$

and in the second,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi$

$\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi$

$\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi$

Then the solutions that fall in the interval $[0,2\pi)$ are

$x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4$

5 0

3 years ago

Read 2 more answers

Order of Operations

Rufina [12.5K]

9 - (a - 7)

Note that - = -1

First, distribute - 1 to all terms within the parenthesis

-1(a - 7) = -a + 7

9 - a + 7

Combine like terms

9 + 7 = 16

-a + 16, or A. 16 - a is your answer

hope this helps

8 0

3 years ago

Read 2 more answers