3 years ago

Find the possible value or values of y in the quadratic equation z^2 - 4z+ 4 =0

1 answer:

5 0

Didn't you mean "Find the possible value or values of z? y is not at all present in this equation.

z^2 - 4z + 4 = 0 can be factored into (z-2)(z-2). Thus, the given equation has two equal, real solutions: z=2 and z=-2.

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Given f(x) = x − 7 and g(x) = x2 . Find g(f(4)). g(f(4)) =

Anastasy [175]

Hey!

Hope this helps...

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To solve this we will first find out what f(x) equals at the given point of 4, and than substitute that answer it for g(f(4))...

f(x) = x - 7

f(4) = 4 - 7 = -3

g(f(4)) = (x - 7)^2 > -3^2 = 9

So...

The answer is: g(f(4)) = 9

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4 years ago

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Lapatulllka [165]

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Step-by-step explanation:

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Therefore, T(°c)= 28t^2

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3 years ago

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jek_recluse [69]

<em>Greetings from Brasil...</em>

Its attached the diagram of the situation.....