Find the possible value or values of y in the quadratic equation z^2 - 4z+ 4 =0
1 answer:
Didn't you mean "Find the possible value or values of z? y is not at all present in this equation.
z^2 - 4z + 4 = 0 can be factored into (z-2)(z-2). Thus, the given equation has two equal, real solutions: z=2 and z=-2.
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