3 years ago

Find the possible value or values of y in the quadratic equation z^2 - 4z+ 4 =0

1 answer:

5 0

Didn't you mean "Find the possible value or values of z? y is not at all present in this equation.

z^2 - 4z + 4 = 0 can be factored into (z-2)(z-2). Thus, the given equation has two equal, real solutions: z=2 and z=-2.

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Round 46,750 to the nearest thousand.

Salsk061 [2.6K]

Answer:

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Step-by-step explanation:

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3 years ago

Help please, I'm desperate!

Luden [163]

B. 2.8
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find three numbers whose sum is 32 if the second is 1 more than the first and the first is 4 less than the third

Alex777 [14]

X+y+z=32
x=z-4
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Hope this helps :)

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3 years ago

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3 years ago

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Sphinxa [80]

Answer:

All payments will be made at the end of the year by using the present value of inflows

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