Greetings!

"<span>Paula is now four times the age of Lynn. Lynn will be 16 in 10 years. How old was Paula four years ago?"

If Lynn will turn sixteen in ten years, she must be 6 at the current moment:
16-10=6

Since Paula is 4 times the age of Lynn, Paula must be:
6(4)
=24

24-4
=20

Paula was 20 years old, 4 years ago.

Hope this helps.
-Benjamin
</span>

3 0

3 years ago

Choose all the numbers that are part of Integers.

Aleksandr [31]

Answer:

all except 5/6

Step-by-step explanation:

All of the numbers listed are in the set of integers, except for the fraction 5/6. It is a rational number, but not an integer.

___

If by "part of integers" you mean that the number can be multiplied by some integer value to make an integer, then 5/6 is "part of 5". It is 1/6 of the integer 5.

3 0

3 years ago

How do I do this? I’m not sure can anyone help?

eduard

value of x= 7√3

Hope it helps you...

8 0

2 years ago

Read 2 more answers

An insurance company sells automobile liability and collision insurance. Let X denote the percentage of liability policies that

qaws [65]

Answer:

-764.28

Step-by-step explanation:

Given the joint cumulative distribution of X and Y as

$F(x,y) = \frac{xy(x+y)}{2000000}\ \ \ \, \ 0\leq x100, 0\leq y\leq 100$

#First find $F_x$ and probability distribution function , $f_x(x)$ :

$F_x(x)=F(x,100)\\\\\\=\frac{100x(x+100)}{2000000}\\\\\\\\=\frac{100x^2+10000x}{2000000}\\\\\\=>f_x(x)=\frac{x}{10000}+\frac{1}{200}$

#Have determined the probability distribution unction , $f_x(x)$ , we calculate the Expectation of the random variable X:

$E(X)=\int\limits^{100}_0 \frac{x^2}{10000}+\frac{x}{200} dx \\\\\\\\=|\frac{x^3}{30000}+\frac{x^2}{400}|\limits^{100}_0\\\\=58.33\\\\$

#We then calculate $E(X^2)$ :

$E(X^2)=\int\limits^{100}_0 \frac{x^3}{10000}+\frac{x^2}{200}\ dx\\\\=\frac{x^4}{40000}+\frac{x^3}{600}|\limits^{100}_0=4166.67\\\\Var(X)=E(X^2)-(E(X))^2=4166.67-58.33^2\\\\Var(X)=764.28$

Hence, the Var(X) is 764.28

4 0

3 years ago

Find the HCF of X5 y3 z2 and X2 y2 z​

Find the HCF of X5 y3 z2 and X2 y2 z