Find the HCF of X5 y3 z2 and X2 y2 z
1 answer:
You might be interested in
Answer:
E'F' and EF are equal in length
Step-by-step explanation:
we have
The coordinates of point E(-3,2) and F(-1,2)
we know that
The rule of the reflection across the x-axis is
(x,y) ------> (x,-y)
so
Applying the rule of reflection across the x-axis
E(-3,2) -------> E'(-3,-2)
F(-1,2) --------> F'(-1,-2)
using a graphing tool
see the attached figure to better understand the problem
therefore
E'F' and EF are equal in length
