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kakasveta [241]
3 years ago
6

How to solve by elimination2x-y=32 and y -5x=13

Mathematics
2 answers:
JulijaS [17]3 years ago
5 0


{2x-y=32

{<u>y-5x=13      </u>(+)

<em>(2x-y)+(y-5x)=32+13</em>

2x-y+y-5x=45

-3x=45    /:(-3)

x=-15

2x-y=32

2*(-15)-y=32

-30-y=32

-y=62

y=-62

<u>The answer:</u> (-15; -62)

erik [133]3 years ago
3 0
2x-y=32
y-5x=13

transform the second equation to make the elimination possible
2x-y=32
-5x+y=13

now, our ys match, and we can drop them out

     2x-y=32
+
     <u>-5x+y=13
</u>     -3x+0=45
       
<u>x= -15
</u>
Now we use the meaning of x in one of the original equations

2*(-15)-y=32
-y=32+30
y=-62

The answer is (-15;-62)

If you need more help, please, see
http://www.domymathhomework.net/



<u />

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