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3 years ago

General solution to differential equation dy/dx=100x+xy

1 answer:

8 0

Dy/dx - xy = 100x

this a first order linear differential equation which can be solved using an integrating factor.

I. F. = e^INT(-xdx) = e^(-1/x^2)

now multiply each term by the IF to solve it

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How do you graph this?

Gemiola [76]

Answer:

You need more information to graaph this.

Step-by-step explanation:

6 0

2 years ago

Do u simplify 7 wholes and 8/10

SSSSS [86.1K]

Answer: Simplify 8/10 which is 4/5.

Step-by-step explanation:

7 0

3 years ago

F(x)=|3x+5|+6 g(x)=7 find (f+g) (x).

horrorfan [7]

Answer:

$(f+g) (x)=\mid 3x+5\mid+13$

Step-by-step explanation:

Operation of Functions

Given:

$f(x)=\mid 3x+5\mid+6$

$g(x)=7$

The sum of (f+g) (x) is:

$(f+g) (x)=\mid 3x+5\mid+6+7$

We cannot operate with the expression inside the absolute bars, thus:

$\boxed{(f+g) (x)=\mid 3x+5\mid+13}$

8 0

3 years ago

HELP PLEASE WILL MARK BRAINLIEST!!

Arte-miy333 [17]

Answer:

Answer is option d)346.4 ft

Step-by-step explanation:

$from \: the \: figure \\ AB = 300 \: ft \: \: \: angle \: C = 60 \:( theta)\: degress \\ in \: triangle \: ABC \: using \: tan \: theta\\ \tan(60) = \frac{opposite \: side}{adjacent \: side} \\ \tan(60) = \frac{300}{BC} \\ \sqrt{3} = \frac{300}{BC} \\ BC = \frac{300}{ \sqrt{3} } \\ BC = 100 \sqrt{3} ft \\ then \: in \: triangle \: ABD \: using \: tan \: theta \\ angle \: D = 30 \: degrees \: (theta) \\ \tan(30 ) =\frac{opposite \: side}{adjacent \: side} \\ \tan(30) = \frac{300}{BD} \\ \frac{1}{ \sqrt{ 3} } = \frac{300}{BD} \\ BD = 300 \sqrt{3} \\ CD = BD - BC \\ = 300 \sqrt{3 } - 100 \sqrt{3} \\ = (300 - 100) \sqrt{3} \\ = 200 \sqrt{3 } \\ = 200 \times 1.732 \\ = 346.4 \: ft$

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

7 0

3 years ago

Find the percent of increase from 1.5 inches to 6 inches.

Komok [63]

Well, from 1.5 to 6 is a 4.5 difference.

now, if we take 1.5 to be the 100%, what is 4.5 off of it in percentage?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1.5&100\\
4.5&p
\end{array}\implies \cfrac{1.5}{4.5}=\cfrac{100}{p}\implies p=\cfrac{4.5\cdot 100}{1.5}$

8 0

3 years ago