Points A and C are the endpoints of one diagonal. Its slope will be
.. (5-(-1))/(-1-(-5)) = 6/4 = 3/2
Points B and D are the endpoints of the other diagonal. Its slope will be
.. (-2-6)/(3-(-9)) = -8/12 = -2/3
The diagonals cross at right angles, so the figure is a rhombus or a kite.
The midpoints of the diagonals are
.. (A +C)/2 = (-5-1, -1+5)/2 = (-3, 2)
.. (B +D)/2 = (-9+3, 6-2)/2 = (-3, 2)
The midpoints of the diagonals are the same. The diagonals are perpendicular bisectors of each other, so the figure is a rhombus.
Answer:
Step-by-step explanation:
2. Should be 500
8. Should be 290
The rest are correct
Since M divides segment AB into a ratio of 5:2, we can say that M is 5/(5+2) of the length of AB. Therefore 5/7 × AB.
distance of AB = d
5/7×(x2 - x1) for the x and 5/7×(y2 - y1) for the y
5/7×(8 - 1) = 5/7 (7) = 5 for the x
and 5/7×(16 - 2) = 5/7 (14) = 10 for the y
But remember the line AB starts at A (1, 2),
so add 1 to the x: 5+1 = 6
and add 2 to the y: 10+2 = 12
Therefore the point M lies exactly at...
A) (6, 12)