I found the complete problem.
If Alice divides it into two trapezoids, the area formula would be: A = [(a+b) / 2] * h
Trapezoid 1
A = [(7.5 + 15)/2 * 5
A = (22.5/2) * 5
A = 11.25 * 5
A = 56.25 sq. ft
Trapezoid 2
A = [(5 + 10)/2 * 7.5
A = (15/2) * 7.5
A = 7.5 * 7.5
A = 56.25 sq. ft
Total area = 56.25 + 56.25 = 112.50 sq. ft.
The answer is: -4/a^2 b^2
Answer:
The question does not have value of height (in the image)
the barn in shape of a cuboid with a half cylinder.
volume of barn = volume of cuboid + volume of cylinder/2

here,

b=6 m
l=10 m
so, 2r=6. thus, r=3,

which approximately,
141.3+60h
for storing all of the hay
141.3+60h≥600
h≥7.644
so..
check if h is less than 7.644, he would not be able to store all of the barn.
mark brainliest please.
Answer:
![c(t) = 120 [0.7]^{t}](https://tex.z-dn.net/?f=c%28t%29%20%3D%20120%20%5B0.7%5D%5E%7Bt%7D%20)
Step-by-step explanation:
At the moment a certain medicine is injected, its concentration in the bloodstream is 120 milligrams per liter.
From that moment forward, the medicine's concentration drops by 30% each hour.
Therefore, the medicine concentration c(t) in mg/liters after t hours will be modeled as
![c(t) = c(0) [1 - \frac{30}{100}]^{t}](https://tex.z-dn.net/?f=c%28t%29%20%3D%20c%280%29%20%5B1%20-%20%5Cfrac%7B30%7D%7B100%7D%5D%5E%7Bt%7D%20)
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. (Answer)
Answer:
Step-by-step explanation:
First of all you have to put the zeros into factor form.
y1 = (x + 2)(x - 5)
Notice that the x changes sigh. You say that the zeros are -2 and 5. To get y1 to go to zero, you must make x the opposite sign of what you are given.
Now you have to expand the factored form to get the standard form
y = x^2 + 2x - 5x - 10
y = x^2 - 3x - 10
That's not the right answer.
f(0) = 30 but you have - 10 at the end so you have to multiply the factored form by - 3
-3(f(x)) = -3(x + 2)(x - 5)
-3(f(x)) = -3(x^2 - 3x - 10)
f(x) = -3x^2 + 9x + 30
f(0) = -3(0)^2 + 9(0) + 30
f(0) = 30
The quadratic still has roots of (x +2)(x - 5) but that 3 makes the y intercept = 30.
See the graph below.