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vladimir1956 [14]
3 years ago
10

In a sample of 1000 adults, 150 said they are very confident in the nutritional information on restaurant menus. for us adults a

re selected at random without replacement. find the probability that all four us adults are very confident in the nutritional information on menus
Mathematics
1 answer:
lions [1.4K]3 years ago
6 0
There are 150 confident adults out of 1000.
Selecting four at random withOUT replacement
Probability that all four are confident
=(150/100*149/999*148/997*147/996)
=150!/146! / (1000!/996!)
= 7301/14925090
= 0.00048918

(check: answer < (150/1000)^4=0.00050625, ok)

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