Can i have help please

How can the next term in the infinite sequence 1,5,12,22,35.... be generated ?

lukranit [14]

Answer:

5322 21 es respusta dissso queridoo burro

7 1

3 years ago

What is the solution for line one: y=-2x+1 line two: -2x-3

Oliga [24]

The slope-intercept form is

y=mx+b

, where m is the slope and b is the y-intercept.

y=mx+b

Find the values of

m

and

b

using the form

y

=

m

x

+

b

.

\m

=

2

b

=

−

3

The slope of the line is the value of

m

, and the y-intercept is the value of

b

.

Slope:

2

y-intercept:

(

0

,

−

3

)

Any line can be graphed using two points. Select two

x

values, and plug them into the equation to find the corresponding

y

values.

Tap for fewer steps...

Find the x-intercept.

Tap for more steps...

x-intercept(s):

(

3

2

,

0

)

Find the y-intercept.

Tap for more steps...

y-intercept(s):

(

0

,

−

3

)

Create a table of the

x

and

y

values.

x

y

0

−

3

2

0

m

=

2

b

=

−

3

The slope of the line is the value of

m

, and the y-intercept is the value of

b

.

Slope:

2

y-intercept:

(

0

,

−

3

)

Any line can be graphed using two points. Select two

x

values, and plug them into the equation to find the corresponding

y

values.

Tap for fewer steps...

Find the x-intercept.

Tap for more steps...

x-intercept(s):

(

3

2

,

0

)

Find the y-intercept.

Tap for more steps...

y-intercept(s):

(

0

,

−

3

)

Create a table of the

x

and

y

values.

x

y

0

−

3

2

0

I'm so sorry it layed out like this my computer is being st00pid

6 0

3 years ago

Read 2 more answers

Find the value of A and B what theorem did you use

balandron [24]

Answer:

Show a picture so I can help

4 0

3 years ago

Read 2 more answers

Simplify to the lowest terms

Black_prince [1.1K]

Answer:

1/2

Step-by-step explanation:

divide the numerator & denominator by 4

4 0

3 years ago

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

3 years ago

Can i have help please ​

Can i have help please