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Oksanka [162]
2 years ago
6

69) Half-way to the center of a planet of uniform density, your weight compared to that at the surface would be :

Mathematics
1 answer:
mel-nik [20]2 years ago
7 0

Answer:

One- half

Step-by-step explanation:

Since the density is uniform  

Mass of the sphere = [(4/3) π r^3] d

where d is the uniform density.

Mass of the sphere = [(4/3) π d] r^3 = k r^3

where k = [(4/3) π d] is a constant  

Weight = mg = G m M / r^2 = G m [k r^3] /r^2 = G m k r

Using Gauss’ law for gravitation,

Half way to the center of a planet the weight is only due to the inner sphere and the outer sphere does not contribute to his weight,  

Inside his weight is mg’ = (G m k  r) /2   = mg/2  

Answer is one-half.

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A model scale is 1 cm = 8m.<br> If the actual object is 40 meters, the model is<br> ____ cm long.
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Find an equation for the line that passes through the points (1, -1) and (-3, 1).
saul85 [17]

Answer:

<h3>y = - 1/2x - 1/2</h3>

Step-by-step explanation:

Equation of line is y = mx + c

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Equation of the line using point

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Hope this helps you.

3 0
3 years ago
I don't get this can somebody help me
Alex17521 [72]
2x° + 1 + x° - 6 + 59°= 360°

3x° + 54° = 360°

3x = 306°

x = 102°

2(102°) + 1°= 204° + 1° = 205°

102° - 6°= 96°

205° + 96° + 59°= 360°
7 0
3 years ago
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