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Ilia_Sergeevich [38]
3 years ago
13

Need help will give brainlest for correct answer and explanation.

Mathematics
1 answer:
solmaris [256]3 years ago
8 0

Answer:

Step-by-step explanation:

Because a function can only have one value of y for one value of x (see vertical line test) only A and D could be parts of the function.

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PLEASE HELP ME I AM TAKING A TEST AND I NEED HELP!!!
zhannawk [14.2K]
Part A.
y=4x+3

Part B.
11=4x+3
8=4x
2=x
2 dollars

Part C.
4(3)+4(2)=12+8=20

It would be enough if there is no sales tax.

Hope this helps!
Your fortune is "Only one fortune a day!"
3 0
3 years ago
Please help asap 50 pts
gregori [183]
I believe the answer is C. It doesn't make sense to drop an object from -16 feet, and it doesn't make sense to have a -120 in the equation. It should be positive for it to come out right.
3 0
3 years ago
Read 2 more answers
Choose the correct simplification of the expression 4 times b all over a to the power of negative 10.
yKpoI14uk [10]
<span><span>an</span>=<span>1<span>a−</span></span></span><span>4a10b</span>n hope i helped
5 0
3 years ago
Prove the identity (cosx+cosy)^2+(sinx-siny)^2= 2+2cos(x+y)
astra-53 [7]
(cos(x) + cos(y))^2 + (sin(x) - sin(y))^2 Remove the brackets

cos^2(x)
+ cos^2(y) + 2cos(x)*cos(y) + sin^2(x) - 2(sin(x)*sin(y) + sin^2(y) Combine these two in bold to make 1 because sin^2(x) + cos^2(x) = 1

1 + cos^2(y) + 2cos(x)*cos(y) - 2*sin(x)*cos(y) + sin^2(y) 
These two in bold also make 1

2 + 2cos(x)*cos(y) - 2*sin(X)*sin(y) Bring out a common factor of 2
2 +2(cos(x)*cos(y) -  sin(x)*sin(y) )

but cos(x+y ) = cos(x)*cos(y) - sin(x)*sin(y)

2 + 2* cos(x + y) is your final answer. 

4 0
3 years ago
Read 2 more answers
R s + 14s when r=6 and s=1/4
poizon [28]
Answer: 5

Explanation:
Basically you just change the letter for the number since R equals 6 then in the equation it would be 6 instead of R. Then for S, S would equal 1÷4 which equals 0.25. Then you plug in the numbers into your equation so look something like this 6 x 0.25 + 14(0.25) and all that together equals 5.

Hope this helped :)
8 0
3 years ago
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