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scoundrel [369]
3 years ago
13

10 points for 2 questions and i get one wrong whats my percentage??

Mathematics
2 answers:
Virty [35]3 years ago
6 0
50% you got half wrong, so I think you got 5 points
NeTakaya3 years ago
6 0
2 questions would be 100%

1 question would be 1/2 of that, 100 / 2 = 50%
 and you would get 5 points
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What is the minimum value of the objective function, C with given constraints? C=5x+3y {⎨x+3y≤9 {5x+2y≤20 {x≥1 {y≥2
Solnce55 [7]

Answer:

The answer is below

Step-by-step explanation:

Plotting the following constraints using the online geogebra graphing tool:

x + 3y ≤ 9         (1)

5x + 2y ≤ 20    (2)

x≥1 and y≥2      (3)

From the graph plot, the solution to the constraint is A(1, 2), B(1, 2.67) and C(3, 2).

We need to minimize the objective function C = 5x + 3y. Therefore:

At point A(1, 2): C = 5(1) + 3(2) = 11

At point B(1, 2.67): C = 5(1) + 3(2.67) = 13

At point C(3, 2): C = 5(3) + 3(2) = 21

Therefore the minimum value of the objective function C = 5x + 3y is at point A(1, 2) which gives a minimum value of 11.

3 0
3 years ago
Which answer is the solution set in simplest form?
ANTONII [103]
In this question there is 1 equation with 1 unknown variable. So it is absolutely possible to find the value of the unknown variable "x".
(4x - 1)/3 = 7/1
4x -1 = 7 * 3
4x - 1 = 21
4x = 21 + 1
4x = 22
x = 22/4
  = 11/2
So the value of the unknown variable x is 11/2. So the correct option is option "d". Hope i have answered your question correctly and helped you to understand the method by which these problems should be done.
3 0
3 years ago
Hey can anyone pls help me in dis real quick!!!!!
ser-zykov [4K]

Answer:

1) you use any parallel lines or rectangles we can double the triangle to get the area and then divide by 2 as we know the length is 92.5yards and we know the width is 53.5 yards.

We would x these by each other and then divide by 2.

We have the width 53 1/2 yards wide and convert this to decimal if we want.

= 53.5 yards.

We then can count the yards for the length =  90 hash marks = 90 yards+ 2.5

= 92.5yards.

We square then add to find the hypotenuse diagonal line but it is an estimate as the lines inscribed subtends into the corner and it becomes a little larger as bottom line is used. Diagonal is found after by doing a reverse equation on the area.

53.5 x 92.5 then divide by 2 = 4948.75/2 = 2474.375

then 2474.375/ 26.75 = 92.5

This proves the line is isosceles and also find the height of the triangle.

But only as an estimate as the actual line distends

Last answer is B and W are equal measures this is because we do not see a right angle and if we bisected the triangle from the goal line to the left side we would prove the midpoint goal line is actually equal and makes lines of play isosceles where two sides are the same at point B and W.

So the answer is 1 yard as B runs the length of the goal back to a position of diagonal run.

The diagonal length is 92.5 yards

Step-by-step explanation:

8 0
4 years ago
The height and length of a right rectangular prism are each 12 cm. The surface area of the prism is
RideAnS [48]

Answer:

99

Step-by-step explanation:

8 0
3 years ago
What are the 6 multiples of 2/5
Iteru [2.4K]
Some examples of multiples of 2/5 are 4/10, 6/15, 8/20, 10/25, 12/30, and 14/35.
4 0
3 years ago
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