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qaws [65]
3 years ago
14

There are 9 balls in a hat the balls are numbered 1-9 you need to choose 3 of the balls. How many possible combinations are ther

e
Mathematics
1 answer:
choli [55]3 years ago
8 0
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There are 57 variations that are above and then times that by 9 because the various will never repeat the same number like when you move onto 2's you'd replace all the 2 with 1's and so on and so forth

The answer is 513 variations 
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1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING
iogann1982 [59]

If

y=\displaystyle\sum_{n=0}^\infty a_nx^n

then

y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n

The ODE in terms of these series is

\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0

\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0

\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}

We can solve the recurrence exactly by substitution:

a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0

\implies a_n=\dfrac{(-2)^n}{n!}a_0

So the ODE has solution

y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}

which you may recognize as the power series of the exponential function. Then

\boxed{y(x)=a_0e^{-2x}}

7 0
3 years ago
Y = 5x + 7<br> 2x + y = -5<br> Are the equations parallel,<br> perpendicular, or neither?
Nezavi [6.7K]

Lines are neither perpendicular nor parallel.

Step-by-step explanation:

Step 1:

In equation 1, Y = 5X + 7

In equation 2,  Y = -2X -5

Step 2:

Slope Intercept form Y =mX +c

Where m = Slope

Slope of line 1 = 5

Slope of line 2 = -2

m1  is not equal to m2. Hence it is not parallel.

m1  × m2 is not equal to -1. Hence they are not perpendicular.

3 0
3 years ago
What is the probability of getting exactly 5 “heads” in 10 coin flips ?
castortr0y [4]

There are \dbinom{10}5=\dfrac{10!}{5!(10-5)!}=252 ways of getting exactly 5 heads in 10 tosses. There are 2^{10}=1024 possible outcomes. So the probability of getting exactly 5 heads is

\dfrac{252}{1024}=\dfrac{63}{256}\approx24.61\%

6 0
3 years ago
Read 2 more answers
The Pi Mu Epsilon mathematics honorary society of Outstanding Universitywishes to have a picture taken of its six officers. Ther
boyakko [2]

Answer:

720

Step-by-step explanation:

I will use the following counting principle:

Product rule: if there are n ways of doing something, and m ways of doing another thing, there are n×m ways of doing both things.

First, we have to choose the 3 people that will be in the first row. This is a 3-element subset of  the set of six people, therefore there are \binom{6}{3}=20 ways of doing this.

Now, we have to arrange the order of the 2 lrows. Each one has 3 people, so there are 3!=6 ways to form one rows. Hence, there are 3!²=36 ways of arranging the two rows.

By the product rule, there are 20×36=720 ways of arrange the officers.

8 0
3 years ago
The average height of 8 adults is 1.8 m. What is the sum of their heights? How do I work this out without a calculator?
Katen [24]
Well, the average of a sum of number is found by adding each given number and dividing that number by the amount of given numbers. 
Example: 5+4+3+8=20 
                and 20/4 = 5, the average of the numbers
Multiply 1.8 by 8.0 using this format:

1.8
x8.0
--------


Hope this helped
5 0
3 years ago
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