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Debora [2.8K]
2 years ago
14

Let A be the set of integers, and let B be the set of rational numbers.

Mathematics
2 answers:
Ilya [14]2 years ago
7 0

Answer:

Step-by-step explanation:

A ∪ B = Q     (set of rational numbers)

A ∩ B = Z      (set of integers)

yaroslaw [1]2 years ago
4 0
Why are you not able to see all of the cellular structures under the microscope? How are the cell diagrams in the text both helpful and limiting in understanding cellular structure

why are you not able to see all of the cellular structures under the microscope? How are the cell diagrams in the text both helpful and limiting in understanding cellular structure

why are you not able to see all of the cellular

why are you not able to see all of the cellular structures under the microscope? How are the cell diagrams in the text both helpful and limiting in understanding cellular structure


why are you not able to see all of the cellular structures under the microscope? How are the cell diagrams in the text both helpful and limiting in understanding cellular structure

structures under the microscope? How are the cell diagrams in the text both helpful and limiting in understanding cellular structure
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Triangle ABC is shown below. Triangle A B C is shown. The length of side A B is 2 x, the length of side B C is 4 x minus 10, and
Sedbober [7]

Answer:the length of line segment AC is 14

Step-by-step explanation:

The diagram is shown in the attached photo

Since Angle A B C and B C A are congruent. It means that they are equal. An isosceles triangle is a triangle that has two equal sides and two equal base angles. Since Angle A B C and B C A are equal, it means that the triangle is an isosceles triangle. It also means that sides AC and AB are equal. The expression becomes

3x - 7 = 2x

3x - 2x = 7

x =7

To determine the length of line segment AC. We will substitute x = 7 into 3x - 7. It becomes

3×7 - 7 = 21 - 7 = 14

6 0
3 years ago
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Let X be a normal random variable with mean 40 and standard deviation 2. Find P(X < 28).
Vikki [24]

Answer:

0

Step-by-step explanation:

Given :

Mean = 40 ; Standard deviation = 2

P(x < 28)

Obtain the Zscore :

Z = (x - mean) / standard deviation

P(Z < (28 - 40) / 2))

Z = (28 - 40) / 2

Z = - 12 / 2

Z = - 6

P(Z < - 6) = 0.000000

5 0
3 years ago
in the apex republic, 8% of the population was unemployed in may of 2006. if there were 176,000,000 people willing to work in th
docker41 [41]
Take 176000000 and multiply by 8% (or 0.08)

176000000 * 0.08 = 14,080,000 unemployed
3 0
3 years ago
Read 2 more answers
What is the arc length of arc CD in the circle below?
lord [1]
The length of the arc intercepted by a central angle is the ratio of the angle to 360 degrees times the circumference. From the given values above,
                            S = (30° / 360°) x 2 x π x (6 ft)
                                 S = π
The angle intercepted an arc which measures π feet. The answer is letter A. 
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3 years ago
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A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
3 years ago
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