(2x - 1)(x + 2y - 3) =
2x(x + 2y - 3) + (-1)(x + 2y - 3) =
2x^2 + 4xy - 6x - x - 2y + 3 =
2x^2 + 4xy - 7x - 2y + 3
idk i am in 6th grade idk
Answer:
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Answer:The integers are -13, -12 and -11.
Step-by-step explanation:
Let the four numbers be n, n+1, n +2, and n+3
Therefore (n )+ (n+1 )+(n+2) + (n +3) = -46
4n + (1 +2+3) = -46
4n + 6= -46
Subtract 6 from both sides to get the value of n
4n +6 - 6= -46 -6
4n = -52
Divide both sides by 4
n = -52/4
n = -13
Therefore, n + 1 = -13 + 1= -12
n + 2= -13 + 2 = -11
The integers are -13, -12 and -11.
I hope this helps, please mark as brainliest.
Answer:
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Step-by-step explanation: