Answer:
16
Step-by-step explanation:
We can list out each of the numbers' prime factors first before deciding their greatest common factor.
16: 2 × 2 × 2 × 2
48: 2 × 2 × 2 × 2 × 3
As you can see the bolded parts, these are the common factors of the two numbers. To find the greatest common factors, we just have to multiply all their common factors together.
Greatest common factor of 16 & 48: 2 × 2 × 2 × 2 = 16
Answer:
9.5
Step-by-step explanation:
Find the sample variance for the data 9,12,9,14,6. Round the answer to one decimal place. Sample variance.
Step 1
We find the Mean of the numbers
Mean = Sum of terms/ Number of terms
Mean = 9+12+9+14+6/5
= 50/5
= 10
Step 2
We find the sample variance
Formula =
(x - Mean)²/n - 1
n = 5
= (9 - 10)²+(12 -10)²+(9- 10)²+(14-10)²+(6-10)²/5 - 1
= 1+ 4+ 1+ 16+16/5 - 1
= 38/5 - 1
= 38/4
= 9.5
Therefore, Sample variance = 9.5
Answer:
unreadable score = 35
Step-by-step explanation:
We are trying to find the score of one exam that is no longer readable, let's give that score the name "x". we can also give the addition of the rest of 9 readable s scores the letter "R".
There are two things we know, and for which we are going to create equations containing the unknowns "x", and "R":
1) The mean score of ALL exams (including the unreadable one) is 80
so the equation to represent this statement is:
mean of ALL exams = 80
By writing the mean of ALL scores (as the total of all scores added including "x") we can re-write the equation as:

since the mean is the addition of all values divided the total number of exams.
in a similar way we can write what the mean of just the readable exams is:
(notice that this time we don't include the grade x in the addition, and we divide by 9 instead of 10 because only 9 exams are being considered for this mean.
Based on the equation above, we can find what "R" is by multiplying both sides by 9:

Therefore we can now use this value of R in the very first equation we created, and solve for "x":
