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2 years ago

HEY CAN ANYONE PLS HELP ME OUT IN DIS PLS!!!

Mathematics

2 answers:

mariarad [96]2 years ago

7 0

Answer:

5 + 1.50x=15.50

1.50x=10.50

x=7

Step-by-step explanation:

Let x be the number of movies rented

solve for x

x=7

nirvana33 [79]2 years ago

3 0

Answer:

he rented 7 movies

Step-by-step explanation:

$15.50-how much the membership is=total/movie bill

$15.50-5=10.50

10.50/1.50=7

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Allyson Greve has calculated her federal taxable income to be $45,300. She pays a state income tax rate of 3% on her federal tax

valentinak56 [21]

Answer:

1,359

Step-by-step explanation:

3% of 45,300 is 1,359

4 0

2 years ago

In a large population, 3% of the people are heroin users. A new drug test correctly identifies users 93% of the time and correct

kari74 [83]

Answer:

(a) The probability tree is shown below.

(b) The probability that a person who does not use heroin in this population tests positive is 0.10.

(c) The probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d) The probability that a randomly chosen person from this population tests positive is 0.1249.

(e) The probability that a person is heroin user given that he/she was tested positive is 0.2234.

Step-by-step explanation:

Denote the events as follows:

X = a person is a heroin user

Y = the test is correct.

Given:

P (X) = 0.03

P (Y|X) = 0.93

P (Y|X') = 0.99

(a)

The probability tree is shown below.

(b)

Compute the probability that a person who does not use heroin in this population tests positive as follows:

The event is denoted as (Y' | X').

Consider the tree diagram.

The value of P (Y' | X') is 0.10.

Thus, the probability that a person who does not use heroin in this population tests positive is 0.10.

(c)

Compute the probability that a randomly chosen person from this population is a heroin user and tests positive as follows:

$P(X\cap Y)=P(Y|X)P(X)=0.93\times0.03=0.0279$

Thus, the probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d)

Compute the probability that a randomly chosen person from this population tests positive as follows:

P (Positive) = P (Y|X)P(X) + P (Y'|X')P(X')

$=(0.93\times0.03)+(0.10\times0.97)\\=0.1249$

Thus, the probability that a randomly chosen person from this population tests positive is 0.1249.

(e)

Compute the probability that a person is heroin user given that he/she was tested positive as follows:

$P(X|positive)=\frac{P(Y|X)P(X)}{P(positive)} =\frac{0.93\times0.03}{0.1249}= 0.2234$

Thus, the probability that a person is heroin user given that he/she was tested positive is 0.2234.

6 0

3 years ago

47 divided 985 show how to work it out

Furkat [3]

1. how many times 47 fits on 985? 20×47=940
try higher: 47×21=987. So use 20. subtract 985-940=45. how many times does 47 fit on 45? 0 so the answer should be 20 remainder 45

3 0

3 years ago

Can someone friend me on discord I'm the winged otter#1703

ad-work [718]

Sure, tell me about yourself before though

6 0

2 years ago

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If f(x) = 2x2 + 1, what is f(x) when x = 3? a.1 b.7 c.13 d.19

prohojiy [21]

Answer:

The value of f(x) = $2x^2 + 1$ when x=3 is 19, hence the correct option is ‘d’.

Solution:

A two degree polynomial equation is given in the question.

The equation is:

$F(x)=2 x^{2}+1$

We need to find the value of f(x) when the value of x is 3.

To solve a question like this we have to substitute the given value of x in the given equation and then simplify it.

Now let's substitute the value of x in the given equation.

$F(x)=2(3)^{2}+1$

First we square the number 3 and then multiply it with 2 and then add 1.

This is done because of the BODMAS rule, in which multiplication is given higher preference as compared to addition.

On solving the equation we get,

F(x)=2×9+1

F(x)=18+1

F(x)=19.

Therefore the value of f(x) when x=3 is 19.

Hence the correct option is ‘d’.

4 0

2 years ago

Read 2 more answers