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3 years ago

43.586 to the nearest tenth, hundredth, and one.

1 answer:

5 0

<span>43.586 to the nearest tenth is 43.6. That is because 43.586 is greater than 43.55 and we have to increase the tenth value for 1. And 43.586 to the nearest hunderth is 43.59. That is because 43.586 is greater than 43.585. Finally, 43.586 to the nearest whole number is 44 ( 43.586 is greater than 43.5 ). Hope this helps. Let me know if you need additional help!</span>

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Inessa05 [86]

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3 years ago

Help me please with this question

Gelneren [198K]

You could go both ways with this question, and they're both true:

-- circle "greatest" in both places;

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3 years ago

Levart [38]

Answer: 7

Step-by-step explanation: its correct, trust me

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3 years ago

Read 2 more answers

Consider a data set containing the following values: 70 65 71 78 89 68 50 75 The mean of the preceding values is 70.75. The devi

Leokris [45]

Answer:

If this is the sample data, the sample variance is 125.07 and the sample standard deviation is 11.18

If this is a population data, the population variance is 109.44 and the population standard deviation is 10.46

Step-by-step explanation:

We are given the following data-set:

70, 65, 71, 78, 89, 68, 50, 75

Deviations from the mean

–0.75, –5.75 , 0.25, 7.25, 18.25, –2.75, –20.75, 4.2

Sample size, n = 8

Sample:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

Sum of squares of differences =

0.5625 + 33.0625 + 0.0625 + 52.5625 + 333.0625 + 7.5625 + 430.5625 + 18.0625 = 875.5

$s = \sqrt{\dfrac{875.5}{7}} = 11.18$

$\text{ Sample variance} = s^2 = 125.07$

Population:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

Sum of squares of differences =

0.5625 + 33.0625 + 0.0625 + 52.5625 + 333.0625 + 7.5625 + 430.5625 + 18.0625 = 875.5

$\sigma = \sqrt{\dfrac{875.5}{8}} = 10.46$

$\text{ Population variance} = \sigma^2 = 109.44$

7 0

3 years ago

What is the value of an annuity due at the end of 15 years of quarterly deposits of $2,000.00 with terms of 8 percent compounded

aleksley [76]

That's a hard question/

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3 years ago