Tan B=1.33. If you put tan^-1 and find the angle of A, you’ll get 36.87, so 90-36.87=53.13, then put Tan53.13, you’ll get TanB=1.33
There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:
So 5 people and (3) could be considered as 6 entities:
Since the order matters, we have to use permutation:
¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!
2,162,160 x 6 = 12,972,960 ways.
Another way to solve this problem is as follow:
5 + (3) people are considered (for the time being) as 6 entities:
The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways
So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:
Total number of permutation = 2,162,160 x 6 = 12,972,960
Answer:
s = 2t₁ + t₂
3 possible combinations:
t₁ = 0 min , t₂ = 8 min
t₁ = 1 min , t₂ = 6 min
t₁ = 2 min , t₂ = 4 min
Step-by-step explanation:
The distance covered by a body in uniform motion is given by the following equation:
s = vt
where,
s = distance
v = speed
t = time
For running:
s = s₁
t = t₁
v = 2 miles/min
Therefore,
s₁ = 2t₁
For walking:
s = s₂
t = t₂
v = 1 miles/min
Therefore,
s₂ = t₂
And the total distance will be:
s = s₁ + s₂
<u>s = 2t₁ + t₂</u>
where,
s = total distance covered in miles
t₁ = running time in min
t₂ = walking time in min
Now, the total distance is given as 8 miles:
8 = 2t₁ + t₂
So, the 3 possible combinations of time to satisfy this equation can be:
<u>t₁ = 0 min , t₂ = 8 min</u>
<u>t₁ = 1 min , t₂ = 6 min</u>
<u>t₁ = 2 min , t₂ = 4 min</u>
Answer:
Im not sure how you need the answer so i put it in different forms for you
w=1/4
w=0.25
w=2^-2
Step-by-step explanation:
They are all the same thing
