m∠5 = x + 1
m∠5 = 60°
Solution:
Given data:
Line a and Line b are parallel lines.
The line that crosses both a and b is a transversal line.
m∠1 = x + 1 and m∠6 = 2x + 2.
<em>If two parallel lines cut by a transversal, then their corresponding angles on the same side are congruent.</em>
∠5 and ∠1 are corresponding angles.
⇒ m∠5 = m∠1
⇒ m∠5 = x + 1
Now, ∠5 and ∠6 forms a linear pair.
m∠5 + m∠6 = 180°
x + 1 + 2x + 2 = 180°
3x + 3 = 180°
Subtract 3 from both sides.
3x = 177°
Divide by 3 on both sides.
x = 59°
m∠5 = 59° + 1° = 60°
m∠5 = 60°
Answer:
1.5secs
Step-by-step explanation:
Given the expression that models the height as;
h(t) = -16t²+20t +6
The ball will touch the ground at when h(t) = 0
0 = -16t²+20t +6
Swap
-16t²+20t +6 = 0
Divide through by -2
8t²-10t-3 = 0
Expand using the general formula
t = -(-10)±√(-10)²-4(8)(-3)/2(8)
t = 10±√100+96/16
t = 10±√196/16
t = 10±14/16
t = 10+14/16
t = 24/16
t = 1.5
Hence it will take the ball 1.5secs to hit the ground
Answer:
A ∩ C [ -6, -4 )
Step-by-step explanation:
A ∩ C
-6 ≤ x < -4
[ -6, -4 )
A is the approximate distance
I believe the answer is 42 ft