Answer:
75% of the data will reside in the range 23000 to 28400.
Step-by-step explanation :
To find the range of values :
We need to find the values that deviate from the mean. Since we want at least 75% of the data to reside between the range therefore we have,
Solving this, we would get k = 2 which shows the value one needs to find lies outside the range.
Range is given by : mean +/- (z score) × (value of a standard deviation)
⇒ Range : 25700 +/- 2 × 1350
⇒ Range : (25700 - 2700) to (25700 + 2700)
Hence, 75% of the data will reside in the range 23000 to 28400.
Y = 7.5*200 +500
y = 1500 +500
y = 2000
2000 gallons are in the pool 200 minutes after the pump is turned on.
Answer:
11484m
Step-by-step explanation:
if 1914 = 1hour
Then 6hours= ?
6/1 ×1914
= 11484m