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3 years ago

Question:

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

6 0

Answer:

theres no graph sorry, maybe if u upload it i can help

Step-by-step explanation:

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What is the area of a section of pavement that is 20 ft wide and 70 yd long?

myrzilka [38]

Answer:

A = 4200 ft^2

Step-by-step explanation:

We know the formula for area is

A = l*w

We need to have the same units

convert yd to ft

1 yd = 3ft

Multiply each by 70

70 yds = 210 ft

A = 210 *20

A = 4200 ft^2

6 0

4 years ago

Dale wanted to put a brick border around his circular flower bed The diameter is five feet how much brick will he need for the b

zmey [24]

.......................

4 0

3 years ago

Y=3x²+3x+1,find the value of the discrimination

Rufina [12.5K]

Answer:

Step-by-step explanation:

a = 3

b = 3

c = 1

Discriminate = sqrt(b^2 - 4ac)

Discriminate = sqrt(9 - 4*3*1)

Discriminate = sqrt(9 - 12)

Discriminate = sqrt(-3)

What negative value means that there are no real roots and the y intercept = 1. You should always graph this kind of question, which I am doing for you. I use Desmos which is a very handy program.

You should notice that the minimum is above the x axis. That means there are no real roots, just as the discriminate tells you.

5 0

3 years ago

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0

1 year ago

Given that m∠abc=70° and m∠bcd=110°. Is it possible (consider all cases): Line AB intersects line CD?

lyudmila [28]

Given that m∠abc=70° and m∠bcd=110°. Is it possible (consider all cases): Line AB intersects line CD? Yes, and the answer will be 180° so yeaaa, the statement is possible to intersect to AB and to the line CD.

Step-by-step explanation:

#CarryOnLearning

3 0

3 years ago