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pishuonlain [190]
2 years ago
13

Find the vertex of this parabola: y = -x2 + 6x – 15

Mathematics
2 answers:
Orlov [11]2 years ago
8 0

y =  - x {}^{2}  + 6x - 15

y {}^{  \gamma  }  =  - 2x + 6

y {}^{ \gamma }  = 0

- 2x + 6 = 0

- 2x =  - 6

2x = 6

x = 3

<h3>Substitute x=3 in y=-x²+6x-15</h3>

y =  - (3) {}^{2}  + 6(3) - 15

y =  - 9 + 18 - 15

y =  - 9 + 3

y =  - 6

<h2><em>Vertex:</em><em> </em><em> </em><em>(</em><em>3</em><em>,</em><em>-</em><em>6</em><em>)</em></h2>
m_a_m_a [10]2 years ago
7 0
<h3>hello!</h3>

==============================

In order to find the vertex of a parabola, we use the following formula:

\mathfrak{\displaystyle\frac{-b}{2a} }

Please remember that a parabola looks like this:

\tt{y=ax^2+bx+c}

Now you know what a and b stand for.

In this case, a = -1, and b is 6:

\mathfrak{\displaystyle\frac{-6}{2(-1)} }

Simplify:

\mathfrak{\displaystyle\frac{-6}{-2}}

\mathfrak{3}\\=======================================

<h3>Notes:</h3>
  • Hope everything is clear.
  • Let me know if you have any questions!
  • Enjoy your day!
  • Always remember: Knowledge is Power :)
<h3>Answered by</h3>

\mathcal{DiAmOnD}\\\tt{A~Creative~Helper}}}}

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