Slope = 
So taking 2 points (0,0) and (60,120)
we have slope = (120-0)/(60-0) = 120/60 = 2
general equation of linear graph is y=mx+b with m be the slope
so y=2x+b
Now to find b, just plug any point of the graph in, such as (0,0)
so we get something like 0=2(0) + b => b=0
So your equation is y=2x
H = 5 + ut - 16t^2
When the balls falls back to the ground, h = 0
0 = 5 + 3.2u - 16(3.2)^2
0 = 5 + 3.2u - 163.84
0 = 3.2u - 158.84
3.2u = 158.84
u = 158.84/3.2 = 49.6 ft/s
Required equation is
h = 5 + 49.6t - 16t^2
1. 130°
I don't remember too many specifics from my past math classes, but I always remembered this because that is an upside-down mirror of the 130° angle.
2. 50°
A straight line is 180°, and 180 - 130 = 50.
Answer:
3.) ![\displaystyle y - 4 = 4[x - 1]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%20-%204%20%3D%204%5Bx%20-%201%5D)
2.) ![\displaystyle y + 5 = 2[x + 2]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%20%2B%205%20%3D%202%5Bx%20%2B%202%5D)
1.) ![\displaystyle y + 3 = 1\frac{1}{5}[x + 5]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%20%2B%203%20%3D%201%5Cfrac%7B1%7D%7B5%7D%5Bx%20%2B%205%5D)
Step-by-step explanation:
In the Point-Slope Formula, ![\displaystyle y - y_1 = m[x - x_1],](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%20-%20y_1%20%3D%20m%5Bx%20-%20x_1%5D%2C)
all the negative symbols give the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT SIGNS.
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I am joyous to assist you anytime.
The answer for your question is (x,y)=(4,9)
