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4 years ago

Use the graph of the function f to determine the given limit.

Mathematics

2 answers:

alexandr402 [8]4 years ago

8 0

Answer:

b. -2

Step-by-step explanation:

Here we have to find when lim x ---> 2, what would be the value of f(x).

The value of f(x) is nothing y value in the graph.

From the given graph, we have to see the value of y, when x = 2

The value of y = -2, when x = 2 by looking at the graph.

Therefore, the answer is b. - 2

Hope you will understand the concept.

Thank you.

Naily [24]4 years ago

4 0

Answer:

Choice C is correct

Step-by-step explanation:

From the graph, the value of the function when x approaches 2 would be 8. The point (2, -2) is an undefined point or a point of discontinuity. Therefore, the limit can not be equal to -2. Nevertheless, there is a point marked by a dark circle (2, 8). this means that when x is 2 the value of the function is 8 even though the point does not lie on the straight line.

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Please help! Brainlyest answer!

Fudgin [204]

Answer:

113 feet

Step-by-step explanation:

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3 years ago

Kate's new juicer is able to squeeze

ehidna [41]

Answer:

9 cups per bag

Step-by-step explanation:

1/12 bag = 3/4 cup

12/12 bag = ? cup

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7 0

3 years ago

Read 2 more answers

A small business is looking for rectangular warehouses to store extra merchandise. Warehouse A has an area of 6900 ft2. Warehous

juin [17]

Answer:

The area of the warehouse B is 1150 square feet.

Step-by-step explanation:

Let $x$ , $y$ are the width and length of the warehouse A, in inches. The areas of the each warehouse are described below:

$A_{A} = x\cdot y$ (1)

$A_{B} = \left(\frac{1}{2}\cdot x \right)\cdot \left(\frac{1}{3}\cdot y \right)$ (2)

Where:

$A_{A}$ - Area of the warehouse A, in square inches.

$A_{B}$ - Area of the warehouse B, in square inches.

If we know that $A_{A} = 6900\,ft^{2}$ , then by (1) and (2) we have the following equation:

$A_{B} = \frac{1}{6}\cdot A_{A}$

$A_{B} = 1150\,ft^{2}$

The area of the warehouse B is 1150 square feet.

4 0

3 years ago

Which statement describes the inverse of m(x) = x^2 – 17x?

DochEvi [55]

Given:

The function is

$m(x)=x^2-17x$

To find:

The inverse of the given function.

Solution:

We have,

$m(x)=x^2-17x$

Substitute m(x)=y.

$y=x^2-17x$

Interchange x and y.

$x=y^2-17y$

Add square of half of coefficient of y , i.e., $\left(\dfrac{-17}{2}\right)^2$ on both sides,

$x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

Taking square root on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}$

Add $\dfrac{17}{2}$ on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y$

Substitute $y=m^{-1}(x)$ .

$m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$

We know that, negative term inside the root is not real number. So,

$x+\left(\dfrac{17}{2}\right)^2\geq 0$

$x\geq -\left(\dfrac{17}{2}\right)^2$

Therefore, the restricted domain is $x\geq -\left(\dfrac{17}{2}\right)^2$ and the inverse function is $m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$ .

Hence, option D is correct.

Note: In all the options square of $\dfrac{17}{2}$ is missing in restricted domain.

7 0

3 years ago

16x + 27<br> 14x – 45<br> 25x

Natali [406]

Super easy!

44x
-31x
25x

5 0

3 years ago