now, let's take a peek at the denominators, we have 3 and 8 and 12, we can get an LCD of 24 from that.
Let's multiply both sides by the LCD of 24, to do away with the denominators.
so, let's recall that a whole is "1", namely 500/500 = 1 = whole, or 5/5 = 1 = whole or 24/24 = 1 = whole. So the whole class will yield a fraction of 1/1 or just 1.
![\bf ~\hspace{7em}\stackrel{\textit{basketball}}{\cfrac{1}{3}}+\stackrel{\textit{soccer}}{\cfrac{1}{8}}+\stackrel{\textit{football}}{\cfrac{5}{12}}+\stackrel{\textit{baseball}}{x}~=~\stackrel{\textit{whole}}{1} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{24}}{24\left(\cfrac{1}{3}+\cfrac{1}{8}+\cfrac{5}{12}+x \right)=24(1)}\implies (8)1+(3)1+(2)5+(24)x=24 \\\\\\ 8+3+10+24x=24\implies 21+24x=24\implies 24x=3 \\\\\\ x=\cfrac{3}{24}\implies x=\cfrac{1}{8}](https://tex.z-dn.net/?f=%5Cbf%20~%5Chspace%7B7em%7D%5Cstackrel%7B%5Ctextit%7Bbasketball%7D%7D%7B%5Ccfrac%7B1%7D%7B3%7D%7D%2B%5Cstackrel%7B%5Ctextit%7Bsoccer%7D%7D%7B%5Ccfrac%7B1%7D%7B8%7D%7D%2B%5Cstackrel%7B%5Ctextit%7Bfootball%7D%7D%7B%5Ccfrac%7B5%7D%7B12%7D%7D%2B%5Cstackrel%7B%5Ctextit%7Bbaseball%7D%7D%7Bx%7D~%3D~%5Cstackrel%7B%5Ctextit%7Bwhole%7D%7D%7B1%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bmultiplying%20both%20sides%20by%20%7D%5Cstackrel%7BLCD%7D%7B24%7D%7D%7B24%5Cleft%28%5Ccfrac%7B1%7D%7B3%7D%2B%5Ccfrac%7B1%7D%7B8%7D%2B%5Ccfrac%7B5%7D%7B12%7D%2Bx%20%5Cright%29%3D24%281%29%7D%5Cimplies%20%288%291%2B%283%291%2B%282%295%2B%2824%29x%3D24%20%5C%5C%5C%5C%5C%5C%208%2B3%2B10%2B24x%3D24%5Cimplies%2021%2B24x%3D24%5Cimplies%2024x%3D3%20%5C%5C%5C%5C%5C%5C%20x%3D%5Ccfrac%7B3%7D%7B24%7D%5Cimplies%20x%3D%5Ccfrac%7B1%7D%7B8%7D)
Step-by-step explanation:
1. f(x) = 12x + 1
f(-2) = 12(-2) + 1 = -23
f(0) = 12(0) + 1 = 1
f(3) = 12(3) + 1 = 37
2. p(x) = -8x - 2
p(-2) = -8(-2) - 2 = 14
p(0) = -8(0) - 2 = -2
p(3) = -8(3) - 2 = -26
3. m(x) = -6.5x
m(-2) = -6.5(-2) = 13
m(0) = -6.5(0) = 0
m(3) = -6.5(3) = -19.5
4. s(x) = ⅖x + 3
s(-2) = ⅖(-2) + 3 = -⅘ + 3 = 11/5
s(0) = ⅖(0) + 3 = 3
s(3) = ⅖(3) + 3 = 6/5 + 3 = 21/5
5. h(x) = ¾x - 6
h(-2) = ¾(-2) - 6 = -6/4 - 6 = -30/4
h(0) = ¾(0) - 6 = -6
h(3) = ¾(3) - 6 = 9/4 - 6 = -15/4
Answer:
<em>5 Cylinders</em>
Step-by-step explanation:
<u><em>Hope I helped!!! </em></u>
<u><em>Please let me know if im correct or incorrect :)</em></u>
<em>~Nuha <3</em>
Answer:
she can make 8 batches
Step-by-step explanation:
In this question , we are concerned with calculating the number of batches of cupcakes keith can make.
To make a batch, 5/8 of a cup is required.
Now she has 5 cups. The number of batches she can make will be 5/(5/8) = 5 * 8/5 = 8
