f(x) = 4x - x^2
1)
f(4) = 4(4) - 4^2 = 16 - 16 = 0
f(-4) = 4(-4) - (-4)^2 = -16 - 16 = -32
f(4) - f(-4) = 0 - (-32) = 32
2)
f(3/2) = 4(3/2) - (3/2)^2
f(3/2) = 6 - 9/4 = 15/4
√f(3/2) = √(15/4) = √15 / 2
3)
f(x + h) = 4(x + h) - (x + h)^2
= 4x + 4h -(x^2 + 2xh + h^2)
= 4x + 4h -x^2 - 2xh - h^2
f(x - h) = 4(x - h) - (x - h)^2
= 4x - 4h -(x^2 - 2xh + h^2)
= 4x - 4h -x^2 + 2xh - h^2
So
[f(x + h) -f(x - h) ] / 2h
= [4x + 4h -x^2 - 2xh - h^2 - ( 4x - 4h -x^2 + 2xh - h^2 )] / 2h
=( 4x + 4h -x^2 - 2xh - h^2 - 4x + 4h + x^2 - 2xh + h^2 ) / 2h
= (8h - 4xh) / 2h
= 2h(4 -2x) / 2h
= 4 - 2x
Answer: [f(x + h) -f(x - h) ] / 2h = 4 - 2x
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Answer:
x=80, y=15
Step-by-step explanation:
The angle on the opposite side of 100 will be equal to x
We know it is 180-100 so x=80
We know 6y=90
therfore y = 90/6 which equals 15
so y=15 and x=80
Answer:

Step-by-step explanation:
We can write the equation of a line in 3 different forms including slope intercept, point-slope, and standard depending on the information we have. We have two standard form equations which we will get a slope and a y-intercept from. We will convert each to slope intercept form to get the information. We will then write a new slope-intercept equation and convert to standard form.
3x-5y=7 has the same slope as the line. Let's convert.


The slope is
.
2y-9x=8 has the same y-intercept as the line. Let's convert.


The y-intercept is 4.
We take
and b=4 and substitute into y=mx+b.

We now convert to standard form.

For standard form we need the coefficients of x and y to be not zero or fractions. We need integers but the coefficient of x cannot be negative. So we multiply the entire equation by -5 to clear the denominators.
