I’m assuming ‘dives further’ means to go directly down
the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.
let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)
then this become a simple trig problem:
A)
Let O be the position of of the ship, and C be the original position of the submarine.
therefore, not considering direction
|OC| = 1.78km = 1780m
|CA| = 45m
these are the adjacent and opposite sides of a right angled triangle.
But tan($) = opp/adj = |CA|/|OC| = 45/1780
therefore $ = arctan(45/1780) which is roughly 1.45 degrees,
B)
similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m
tan(¥) = 107/1780
¥ = arctan(107/1780) which is roughly 3.44 degrees
Answer:
224 ounces
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
I. a // b because m∠2 is on a 180° line, which splits the line into two sections, both being 90°. If m∠1=m∠2, then m∠1 is also 90°. The lines a and b are parallel from each other.
II. since m∠1 is 90°, and for a line to be perpendicular to the other line, they would have to be at a 90°. So, a⊥c because they intersect each other at a 90° angle.
Answer:
D.
Step-by-step explanation:
The domain can be understood as being the x whereas the y can be considered as being the range.
We know that in order to find the y, or in order words 
we can simply plug in any x value that we're interested in into 
If we do that with the values of x (or domain) that we have from the problem, we will get
From the results that we got, we know that the answer is D.
Good luck!
Answer:
s=60 :)
Step-by-step explanation:
60/2=30
30+17=47
If you need me to go into more detail don't be afraid to ask :)
