Let be the length of one leg, and
be the length of the hypothenuse. Finally, let
be the measure of the angle between them. Then, the following relation holds:
Plugging your values, we have
Solving for x, we have
Which of the following is a situation in which an equation cannot be solved using the quadratic formula? A.) The coefficient of
1 answer:
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Hello!
To find the slope of the line that passes through the points (3, 6) and (5, 3), we will need to use the slope formula.
Slope formula is .
Now, we should assign the given points as x1, y1 or x2, y2. The point (3, 6) can be assigned to x1, y1, and (5, 3) to x2, y2.
Now, substitute the given points into the slope formula.
Therefore, the slope of the line is choice A, -3/2.
Answer:
Step-by-step explanation:
so when the height is zero, that's when the rocket hits the ground. The equation will have two zeros, but one would be for a negative time, or before the rocket is launched. so we only one the one after the rocket is launched.
use the quadratic formula to solve for x ( which is time)
-124 +- sqrt [ - 4*(-16)*(127) ] / 2 (-16)
-124 +- sqrt [15376 + 8128 ] / -32
-124 +- sqrt [23504 ] / -32
-124 +- 153.310 / -32
if we take the positive part it will become the negative time so skip that one try the negative part 1st
-124 - 153.310 / -32
-277.310 / -32
8.6659 seconds to hit the ground. ( time of flight) aka TOF
8.67 seconds ( rounded to nearest 100th)