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3 years ago

What are the steps for using a compass and straightedge to construct the bisector of ZA?

Mathematics

2 answers:

romanna [79]3 years ago

6 0

The order of the steps is:

Step 1. is the fifth statement

Step 2. is the first statement

Step 3. is the second statement

Step 4. is the third statement

Step 5. is the fourth statement

Step-by-step explanation:

Lets revise the steps of construct the bisector of ∠ A

Steps:

1. Place the point of the compass on point A and draw an arc that

intersects the sides of ∠A

Label the points of intersection as points B and C

2. Place the point of the compass on point B and draw an arc in the

interior of the angle

3. Without changing the opening of the compass place the point of

the compass on point C and draw another arc in the interior of the

angle

4. Label the intersection of the arcs in the interior of the angle as

Point D

5. Use the straightedge to draw AD ray

From the steps above

The order of the steps is:

Step 1. is the fifth statement

Step 2. is the first statement

Step 3. is the second statement

Step 4. is the third statement

Step 5. is the fourth statement

Learn more:

You can learn more about construction in brainly.com/question/3309261

#LearnwithBrainly

gavmur [86]3 years ago

3 0

For those of you who are doin the test rn here are the answers to all of them. Hope this helps! ;) I did the quiz

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3 years ago

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ValentinkaMS [17]

Answer:

The equation of the line that goes through points (1,1) and (3,7) is $\mathbf{y=3x-2}$

Step-by-step explanation:

Determine the equation of the line that goes through points (1,1) and (3,7)

We can write the equation of line in slope-intercept form $y=mx+b$ where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have $x_1=1, y_1=1, x_2=3, y_2=7$

Putting values and finding slope

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{7-1}{3-1}\\Slope=\frac{6}{2}\\Slope=3$

We get Slope = 3

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$y=mx+b\\1=3(1)+b\\1=3+b\\b=1-3\\b=-2$

We get y-intercept b = -2

So, equation of line having slope m=3 and y-intercept b = -2 is:

$y=mx+b\\y=3x-2$

The equation of the line that goes through points (1,1) and (3,7) is $\mathbf{y=3x-2}$

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