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aleksley [76]
3 years ago
14

Prove the following theorem indirectly. We will give you a start.Prove that a triangle cannot have two right angles. A triangle

cannot have two right angles. Suppose a triangle had two right angles.
Mathematics
1 answer:
nordsb [41]3 years ago
4 0
A triangle can't have two right angles because there is 180° in a triangle. Each right angle is 90° so it would be impossible
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Emmy throws a doggy toy up in the air. The path of the toy is modeled by the function f(x)=−x^2+4x+5, where x is the number of f
Molodets [167]

Answer:

9feet

Step-by-step explanation:

Given the path of the toy modeled by the function f(x)=−x^2+4x+5, where x is the number of feet the toy is from Emmy and f(x) is the height of the toy.

AT maximum height, the velocity of the toy will be zero. Hence;

df(x)/dx = 0

-2x + 4 = 0

-2x = -4

x = -4/-2

x = 2

Get the maximum height;

Substitute x = 2 into the given function;

f(x)=−x^2+4x+5

f(2)=−2^2+4(2)+5

f(2) = -4+8+5

f(2) = 9feet

Hence the maximum height of the toy is 9feet

4 0
3 years ago
How many people had a slice of the pizza?
Kobotan [32]
Because of the social divide in todays pizza slices 10 would be the right answer


3 0
3 years ago
A rectangular prism has a length of 11 mm and with a 5 mm. Its height is double its weight. What is the surface area of the pris
kkurt [141]

Answer:

C. 430

Step-by-step explanation:

length: 11

weight: 5

height (double of weight): 10

2 * (5 * 11 + 10 * 11 + 10 * 5)= 430

4 0
3 years ago
Why is it not reasonable to have a linear trinomial with only one type of letter?
Rus_ich [418]
Because you can just simplify to have 1-2 terms only. Eg:
13+2y+4y (this is a trinomial as it has 3 terms) can be simplified to just give 13+6y
5 0
3 years ago
May someone please help me out with this problem? May you also explain it?
gavmur [86]

Answer:

Step-by-step explanation:

Given function is,

f(x) = \sqrt{x}

If the given function is vertically stretched by a scale factor of \frac{3}{2} Or 1.5,

Transformed function will be,

h(x) = \frac{3}{2}[f(x)]

h(x) = \frac{3}{2}(\sqrt{x})

Further function 'h' is shifted 1 units upwards,

g(x) = h(x) + 1

g(x) = \frac{3}{2}(\sqrt{x} )+1

Domain of the function → x ≥ 0 Or [0, ∞)

Range of the function → y ≥ 1 Or [1, ∞)

Transformations done → Parent function f(x) is vertically stretched by a scale factor of \frac{3}{2} then shifted 1 unit upward.

3 0
3 years ago
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