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3 years ago

9/6 divided 1/2 can somebody help please

Mathematics

2 answers:

True [87]3 years ago

6 0

Answer:

Step-by-step explanation:

$\frac{9}{6}$ ÷ $\frac{1}{2}$ = 3

miv72 [106K]3 years ago

5 0

The answer is 3...........

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The watering can that Carlos uses in his vegetable garden holds 5 of a certain unit of liquid volume. When full, how much water

Sedaia [141]

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3 years ago

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Why is a model divided into six sections

stepan [7]

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4 years ago

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Perform the indicated operation. Simplify the result in factored form. ((x - y)/ (x^2 - 1)) * ((x - 1)/(x^2 - y^2))

Scilla [17]

Answer:

The answer to your question is $\frac{1}{(x + 1)(x + y)}$

Step-by-step explanation:

Real operation

$\frac{x - y}{x^{2} - 1} \frac{x - 1}{x^{2} - y^{2}}$

Process

1.- Factor the denominators

$\frac{x - y}{(x + 1)(x - 1)} \frac{x - 1}{(x + y)(x - y)}$

2.- Simplify like terms

Cancel (x - y) and (x - 1) because they are in numerator and the denominator

$\frac{1}{(x + 1)(x + y)}$ This is the answer or you can expand

3.- Expand

$\frac{1}{x^{2} + xy + x + y^{2}}$

3 0

3 years ago

Calculate ZQRP<br> 12 cm<br> Р<br> R<br> 18 cm

gladu [14]

Answer:

<QRP = 48.2°

Step-by-step explanation:

Given:

PR = 18 cm

QR = 12 cm

Required:

<QRP = angle R

Solution:

Reference angle = <R (<QRP)

Adjacent side length = 12 cm

Hypotenuse = 18 cm

Thus:

Cos (R) = 12/18

cos (R) = 0.6667

$R = Cos^{-1}(0.6667)$

$R = 48.1871227$

<QRP = 48.2° (nearest tenth)

8 0

3 years ago

Find the magnitude and direction angle for the vector v = 3 cos 123°i + 3 sin 123°j.

Alika [10]

The vector written in its generic form is given by:
v = lvl cos theta ° i + lvl without theta ° j
Where.
lvl: magnitude of the vector
theta: angle of the vector with respect to the x axis.
For this case we have the following vector:
v = 3 cos 123 ° i + 3 without 123 ° j
Where,
lvl = 3
theta = 123 °
Answer:
The magnitude and direction angle for the vector v is:
D. 3, 123 °

8 0

4 years ago