Answer:
Man' s genotype= Bb
Children's genotype= Bb, Bb and bb for the three children
Explanation:
The gene involved here is that coding for eye color in humans. The allele for brown eyes (B) is dominant over that of blue eyes (b) i.e. brown eyes allele (B) will mask the expression blue eyes allele (b) in an heterozygous state.
A brown-eyed man is crossed with a blue-eyed woman (bb). The woman will be homozygous recessive since the recessive trait can only be expressed in a homologous state. They produce 2 brown-eyed offsprings and 1 blue-eyed offspring.
Note that, for the man who possess the dominant trait (brown eyes), he can either possess a homozygous or heterozygous genotype. Since he produced a recessive phenotyped (blue eyes) offspring when crossed with a blue-eyed woman, it means he donated a recessive allele (b) which combined with that of the woman. Hence, the man has a heterozygous genotype (Bb).
Having known the man's genotype, a cross (see attached image) between Bb and bb will produce four possible offsprings; 2 will be heterozygous brown-eyed (Bb) while the other two will be homozygous blue-eyed (bb).
Since two of their children were brown-eyed, they will have a (Bb) genotype while the blue-eyed child will have a (bb) genotype.
Answer: Sickle-cell disease
Explanation:
Sickle-cell disease is characterized by the presence of a sickle shaped red blood cell, due to the substitution of glutamate with valine in the amino acid sequence of the protein globin portion.
Hence, the sickled shaped globin is unable to transport oxygen efficiently to body tissues, resulting in malfunction of the red blood cell.
It’s monocot because dicots are found in the lower epidermis only
Answer:
Taxonomy is a branch of science that classifies, names, and describes organisms.
Coal is expected to have the highest rate of consumption in 2030.