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Otrada [13]
3 years ago
14

What is the average rate of change for h(x)=x^2+x-6

Mathematics
1 answer:
arlik [135]3 years ago
4 0

\bf slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}\\\\[-0.35em] \rule{31em}{0.25pt}\\\\ h(x)=x^2+x-6 \qquad \begin{cases} x_1=0\\ x_2=3 \end{cases}\implies \cfrac{h(3)-h(0)}{3-0} \\\\\\ \cfrac{(3^2+3-6)~~-~~(0^2+0-6)}{3}\implies \cfrac{(6)-(-6)}{3} \\\\\\ \cfrac{6+6}{3}\implies \cfrac{12}{3}\implies 4

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Read 2 more answers
Which property of real numbers IS shown below?<br> 3 + ((-5) + 6) = (3 + (-5)) + 6
Art [367]

The associative property of real numbers is shown in the number expression 3 + ((-5) + 6) = (3 + (-5)) + 6

<h3>What is an arithmetic operation?</h3>

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.

We have a number expression:

= 3 + ((-5) + 6) = (3 + (-5)) + 6

As we know in the associative property:

a + (b + c) = (a + b) + c

= (3 + (-5)) + 6

Thus, the associative property of real numbers is shown in the number expression 3 + ((-5) + 6) = (3 + (-5)) + 6

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6 0
2 years ago
Triangle ABC has been rotated 90° to create triangle DEF. Write the equation, in slope-intercept form, of the side of triangle A
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the equation in the slope-intercept of the side of triangle ABC that is perpendicular to segment EF is y = x + 1

<h3>How to determine the equation</h3>

From the figure given, we can deduce the coordinates of the sides

For A

A ( 4,2)

For B

B ( 4, 5)

C ( 1, 2)

D ( 2, -4 )

E  ( 5, -4)

F ( 2, -1)

The slope for BC

Slope = \frac{y2 - y1}{x2 - x1}

Substitute the values for both B and C coordinates, we have

Slope = \frac{2- 5}{1 - 4}

Find the difference for both the numerator and denominator

Slope = \frac{-3}{-3}

Slope = 1

We have the rotation for both point ( 0, 1)

y - y1 = m ( x - x1)

The values for y1 and x1 are 1 and 0 respectively and the slope m is 1

Substitute the values

y - 1 = 1 ( x - 0)

y - 1 = x

Make 'y' the subject of formula

y = x + 1

Thus, the equation in the slope-intercept of the side of triangle ABC that is perpendicular to segment EF is y = x + 1

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4 0
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