Answer:
Area of 
ACD = 4 
Area of ABC = 16
Step-by-step explanation:
Given that:
D is a point on AB.
and ABC is a triangle.
AD:DB = 1 : 3
Area of CDB = 12
Kindly refer to the attached image as per the given dimensions and values.
To find:
Area of ACD and Area of ABC = ?
Solution:
Formula for area of a triangle = 
The altitudes of triangles CDB and ACD are equal in dimensions.
Therefore the area of triangles CDB and ACD will be equal to the ratio of their bases.
Area of ACD : Area of CDB = AD: DB = 1 : 3
Area of ACD = 
Area of ABC = Area of ACD + Area of CDB = 12 + 4 = <em>16</em>
Therefore, the answer is:
Area of ACD = 4
Area of ABC = 16
Answer:
Hello,
d.
Step-by-step explanation:
-x + 2 
x + 1 x < 1
ΔTXV is an <span>isosceles triangle because ∡T = ∡X therefore TV = VX.
3x - 24 = 2x + 1 |subtract 2x from both sides
x - 24 = 1 |add 24 to both sides
x = 25
</span>
Your answer would look like this
