3 years ago

21 ≤ 3 + 9x please help me solve the inequality

Mathematics

2 answers:

igomit [66]3 years ago

8 0

Answer:

$x\ge \:2$

Step-by-step explanation:

$21 \le 3 + 9x$

$3+9x\ge \:21$

$3+9x-3\ge \:21-3$

$9x\ge \:18$

$\frac{9x}{9}\ge \frac{18}{9}$

$x\ge \:2$

Anastasy [175]3 years ago

3 0

Answer:

x ≥ 2

Step-by-step explanation:

21 ≤ 3 + 9x

21 - 3 ≤ 9x

18 ≤ 9x

18 ÷ 9 ≤ x

2 ≤ x

x ≥ 2

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