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lora16 [44]
2 years ago
6

Find the work W done by a force of 7pounds acting in the direction 30 degreesto the horizontal in moving an object 7feet from (0

comma 0 )to (7 comma 0 ).
Mathematics
1 answer:
Vikki [24]2 years ago
5 0

Answer:

<em>The work done by the force is 42.4 Joules</em>

Step-by-step explanation:

The force F = 7 pounds

angle to the horizontal that the force acts ∅ = 30°

The object is moved a distance d = 7 feet

The coordinate  (0 comma 0 )to (7 comma 0 ), indicates that the movement started from the origin, and is along the x-axis.

The work done by this force = F cos ∅ x d

==> 7 cos 30° x 7

==> 7 x 0.866 x 7 =<em> 42.4 Joules</em>

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<u>We are given</u>

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Clearly, the shape of the earth is a sphere. Thus, to determine the volume of the earth, we will use a formula that determines the volume of a sphere.

\implies \text{Volume of sphere =} \   \dfrac{4\pi r^{3}}{3}

When we substitute the radius in the formula, we get;

\implies\text{Volume of sphere} = \dfrac{4\pi (640)^{3}}{3}

\implies\text{Volume of sphere} = \dfrac{4\pi (640)(640)(640)}{3}

Take π as 3.14

\implies\text{Volume of sphere} = \dfrac{4\pi (640)(640)(640)}{3}

\implies \text{Volume of sphere} = \dfrac{4(3.14)(640)(640)(640)}{3}

Simplify the numerator;

\implies \text{Volume of sphere} = \dfrac{4(3.14)(640)(640)(640)}{3}

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