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3 years ago

Which of the following equations would graph a line parallel to 3y=2x-x+5

Mathematics

1 answer:

Bumek [7]3 years ago

5 0

That answer is 3y=x+1 I just used my graphing calculator

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What is the value of 4 + 5x when x = 3? 11 12 17 19

kirza4 [7]

19 is the answer 4+5(3)= 4+15=19

8 0

3 years ago

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Given the function h(x) = 3(5)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.

otez555 [7]

We can write the function in terms of y rather than h(x) so that:

y = 3 (5)^x

A. The rate of change is simply calculated as:

r = (y2 – y1) / (x2 – x1) where r stands for rate

Section A:

rA = [3 (5)^1 – 3 (5)^0] / (1 – 0)

rA = 12

Section B:

rB = [3 (5)^3 – 3 (5)^2] / (3 – 2)

rB = 300

B. We take the ratio of rB / rA:

rB/rA = 300 / 12

rB/rA = 25

So we see that the rate of change of section B is 25 times greater than A

7 0

3 years ago

Can someone plz help me solved this problem! I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!

sergeinik [125]

Answer:

a). 8(x + a)

b). 8(h + 2x)

Step-by-step explanation:

a). Given function is, f(x) = 8x²

For x = a,

f(a) = 8a²

Now substitute these values in the expression,

$\frac{f(x)-f(a)}{x-a}$ = $\frac{8x^2-8a^2}{x-a}$

= $\frac{8(x^2-a^2)}{(x-a)}$

= $\frac{8(x-a)(x+a)}{(x-a)}$

= 8(x + a)

b). $\frac{f(x+h)-f(x)}{h}$ = $\frac{8(x+h)^2-8x^2}{h}$

= $\frac{8(x^2+h^2+2xh)-8x^2}{h}$

= $\frac{8x^2+8h^2+16xh-8x^2}{h}$

= (8h + 16x)

= 8(h + 2x)

4 0

3 years ago

Your bank account is sitting on $14,000. You started with a principal balance of $12,500. If the interest rate was 4.5% compound

Simora [160]

Answer:

$t=2.5\ years$

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$t=?\ years\\ P=\$12,500\\P=\$14,000\\ r=4.5\%=4.5/100=0.045$

substitute in the formula above and solve for t

$14,000=12,500(e)^{0.045t}$

Simplify

$14,000/12,500=(e)^{0.045t}$

$1.12=(e)^{0.045t}$

Apply ln both sides

$ln(1.12)=ln[(e)^{0.045t}]$

$ln(1.12)=(0.045t)ln(e)$

Remember that

$ln(e)=1$

$ln(1.12)=(0.045t)$

$t=ln(1.12)/(0.045)$

$t=2.5\ years$

3 0

3 years ago

3(-4x + 8)=.................

Nezavi [6.7K]

Answer:

-144 or 2 5

Step-by-step explanation:

7 0

2 years ago

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